A bus travels from el Paso, texas, to chihuahua, mexico, in 5 hr with an average velocity if 75km/hr to the south. How far is Ch
1 answer:
375km
Explanation:
Given parameters:
Time of travel = 5hr
Average velocity = 75km/hr south
Unknown:
Displacement between Chihuahua and El paso = ?
Solution:
Velocity is the rate of change of displacement of a body with time. It is a vector quantity that has both magnitude and direction;
Velocity =
Since the unknown is displacement;
displacement = velocity x time
input the values;
displacement = 75km/hr x 5hr = 375km
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Answer:
Explanation:
From the given information:
radius = 15 m
Time T = 23 s
a) Speed (v) =
v = 4.10 m/s
b) The magnitude of the acceleration is:
a = 1.12 m/s²
c) True weight = mg
Apparent weight = normal force
From the top;
the normal force = upward direction,
weight is downward as well as the acceleration.
true weight - normal force = ma
apparent weight =mg - ma
= 0.886 m/s²
d)
From the bottom;
acceleration is upward, so:
apparent weight - true weight = ma
apparent weight = true weight + ma
= 1.114 m/s²