Answer:
diameter = 21.81 ft
Explanation:
The gravitational force equation is:
![F=\frac{GMm}{R^{2} }](https://tex.z-dn.net/?f=F%3D%5Cfrac%7BGMm%7D%7BR%5E%7B2%7D%20%7D)
Where:
- F => Gravitational force or force of attraction between two masses
- M => Mass of asteroid 1
- m => Mass of asteroid 2
- R => Distance between asteroids 1 and 2 (from center of gravity)
We also know that the asteroids are identical so their masses are identical:
Since R is the distance between centers of the two asteroids and their diameters are identical (see attachment), we can conclude that:
We don´t know the mass of the asteroids but we know they are composed of pure iron, so we can relate their masses to their density:
This is going to be helpful because the volume of a sphere is:
And know we can write our original force of gravity equation in terms of the radius of the asteroids:
Now let´s plug in the values we know:
mutual gravitational attraction force
gravitational constant![ρ_{iron} =491.5 \frac{lb}{ft^{3} }](https://tex.z-dn.net/?f=%CF%81_%7Biron%7D%20%3D491.5%20%5Cfrac%7Blb%7D%7Bft%5E%7B3%7D%20%7D)
Solve for r and multiply by 2 because 2r = diameter
Result is d = 21.81 Feet
Answer:
According to our principle, when an object is slowing down, the acceleration is in the opposite direction as the velocity. Thus, this object has a negative acceleration. In Example D, the object is moving in the negative direction (i.e., has a negative velocity) and is speeding up.
Answer:toward the ceiling
Explanation:
if you use the right hand rule it will point to the ceiling
Answer:
Magnetic force, F = 0.262 N
Explanation:
It is given that,
Magnetic field of an electromagnet, B = 0.52 T
Length of the wire, ![l = 2r =2\times 2.4=4.8\ cm=0.048\ m](https://tex.z-dn.net/?f=l%20%3D%202r%20%3D2%5Ctimes%202.4%3D4.8%5C%20cm%3D0.048%5C%20m)
Current in the straight wire, i = 10.5 A
Let F is the magnitude of force is exerted on the wire. The magnetic force acting on an object of length l is given by :
![F=ilB](https://tex.z-dn.net/?f=F%3DilB)
![F=10.5\ A\times 0.048\ m\times 0.52\ T](https://tex.z-dn.net/?f=F%3D10.5%5C%20A%5Ctimes%200.048%5C%20m%5Ctimes%200.52%5C%20T)
F = 0.262 N
So, the magnitude of force is exerted on the wire is 0.262 N.