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Galina-37 [17]
3 years ago
11

Which statement is true regarding the relationship between distance and displacement? A) Distance and displacement are always eq

ual. B) Distance is always different than displacement. C) Distance is always less than or equal to displacement. D) Distance is always greater than or equal to displacement.
Physics
2 answers:
evablogger [386]3 years ago
7 0

Answer:

D) Distance is always greater than or equal to displacement.

Explanation:

Since we know that the displacement is shortest distance between initial and final position or we can say it is the straight line distance between initial and final position.

While distance is the total path length of the object while it will move from initial to final position.

So if object moves in a straight line path without any turn then the path length and the displacement is always same.

But if the object move on curved path then displacement is smaller than the distance moved by the object

So here correct answer would be

D) Distance is always greater than or equal to displacement.

jeka943 years ago
3 0
Displacement is a vector quantity whereas distance is scalar quantity.
Distance is the magnitude of displacement. Hence distance is always greater than or equal to displacement.
Option D is correct.

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Initial velocity vector vA has a magnitude of 3.00 meters per second and points 20.0o north of east, while final velocity vector
garri49 [273]

Answer:

5.2\ \text{m/s}

70^{\circ} south of east

Explanation:

v_a = 3 m/s

\theta_a = 20^{\circ} north of east

v_b = 6 m/s

\theta_b = 40^{\circ} south of east = 360-40=320^{\circ} north of east

x and y component of v_a

v_{ax}=v_a\cos \theta\\\Rightarrow v_{ax}=3\times \cos 20^{\circ}\\\Rightarrow v_{ax}=2.82\ \text{m/s}

v_{ay}=v_a\sin\theta\\\Rightarrow v_{ay}=3\times \sin20^{\circ}\\\Rightarrow v_{ay}=1.03\ \text{m/s}

x and y component of v_b

v_{bx}=v_b\cos \theta\\\Rightarrow v_{bx}=6\times \cos 320^{\circ}\\\Rightarrow v_{bx}=4.6\ \text{m/s}

v_{by}=v_b\sin\theta\\\Rightarrow v_{by}=6\times \sin320^{\circ}\\\Rightarrow v_{by}=-3.86\ \text{m/s}

\Delta v=v_b-v_a\\\Rightarrow \Delta v=(4.6-2.82)\hat{i}+(-3.86-1.03)\hat{j}\\\Rightarrow \Delta v=1.78\hat[i}-4.89\hat{j}

Magnitude

|\Delta v|=\sqrt{(-4.89)^2+1.78^2}\\\Rightarrow \Delta v=5.2\ \text{m/s}

Direction

\theta=\tan{-1}|\dfrac{-4.89}{1.78}|\\\Rightarrow \theta=70^{\circ}

The magnitude of the change in velocity vector is 5.2\ \text{m/s} and the direction is 70^{\circ} south of east.

6 0
3 years ago
A grey hound can run about 40/mph is it velocity,acceleration, or speed
loris [4]

Answer: Speed

Explanation:

Speed is the time it takes something to travel a certain distance. Accelaration is the rate at which an object's speed changes. Velocity is a vector of the object's speed and direction.

5 0
3 years ago
When the same force id applied to a smaller area, the pressure is A. Lower B.greater C. Reduced D. The same
irakobra [83]
I believe the correct answer is "B. Greater".
7 0
3 years ago
The work function (energy needed to remove an electron) of gold is 5.1 eV. Two pieces of gold (at the same potential) are separa
scoundrel [369]

Answer:

The value of L is 0.3 nm.

Explanation:

Given that,

Energy \phi= 5.1 eV

Transmission probability = 10⁻³

We need to calculate the value of L

We know that,

Formula of tunneling probability

T=Ge^{-2kL}....(I)

Where,

k=\dfrac{\sqrt{2m(E-U)}}{\hbar}....(II)

Where, m = mass of electron

E = \phi+U

\phi = E-U

Put the value in equation (II)

k=\dfrac{\sqrt{2\times9.1\times10^{-31}\times5.1\times1.6\times10^{-19}}}{1.055\times10^{-34}}

k=1.155\times10^{10} m^{-1}

From equation (I)

ln T=-2kLG

L=\dfrac{ln T}{-2kG}

L=\dfrac{ln 10^{-3}}{-2\times1.155\times10^{10}\times1}

L=2.99\times10^{-10}\ m

L=0.299\times10^{-9}\ m

L=0.3\ nm

Hence, The value of L is 0.3 nm.

7 0
3 years ago
HELP!
notsponge [240]

<em>optical</em><em> </em><em>fibre</em>

\huge \mathfrak \blue{hope \: it \: helps}

7 0
2 years ago
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