Which statement is true regarding the relationship between distance and displacement? A) Distance and displacement are always eq
2 answers:
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Answer:
1. What was the diameter of the hailstone in inches_5.09_ and in cm___12.92___ and in feet ____0.42___?
2. What was the total volume of the hailstone in cubic inches___68.64___ and cubic feet____0.03____?
3. What was the fall velocity of this hailstone in m/s_____2.584____ and in mph___5.78_____?
Explanation:
1. If the circumference (L) of the stone is 16 inches, then from the following equation
1 inch = 2.54 cm = 0.08 ft, so 5.09 inches = 12..92 cm = 0.42 ft
2. The total volume is
3. The fall velocity is V = kd, where k = 20 if d is in cm. Let's calculate the fall velocity in cm.
2.584 m/s = 5.78 mph
Answer:
+5.7 m/s
Explanation:
According to the law of conservation of momentum is that the momentum before the collision is equal to the momentum after the collision. In an equation form it would look like this:
M₁V₁+M₂V₂ = M₁V₁'+M₂V₂'
Where:
M₁ = mass of object 1 (kg)
V₁ = velocity of object 1 before the collision (m/s)
V₁' = Final velocity of object 1 after the collision (m/s)
M₂ = mass of object 2 (kg)
V₂ = velocity of object 2 before the collision (m/s)
V₂' = Final velocity of object 2 after the collision (m/s)
According to your problem you have the following given:
M₁ = 5 g = 0.005kg
V₁ = 3 m/s
V₁' = -5m/s (It bounced off so it is going the other direction)
M₂ = 6g = 0.006kg
V₂ = -1 m/s (It is coming from the opposite direction of the 3-ball)
V₂' = ?
So we plug in what we know and solve for what we don't know.