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Galina-37 [17]
3 years ago
11

Which statement is true regarding the relationship between distance and displacement? A) Distance and displacement are always eq

ual. B) Distance is always different than displacement. C) Distance is always less than or equal to displacement. D) Distance is always greater than or equal to displacement.
Physics
2 answers:
evablogger [386]3 years ago
7 0

Answer:

D) Distance is always greater than or equal to displacement.

Explanation:

Since we know that the displacement is shortest distance between initial and final position or we can say it is the straight line distance between initial and final position.

While distance is the total path length of the object while it will move from initial to final position.

So if object moves in a straight line path without any turn then the path length and the displacement is always same.

But if the object move on curved path then displacement is smaller than the distance moved by the object

So here correct answer would be

D) Distance is always greater than or equal to displacement.

jeka943 years ago
3 0
Displacement is a vector quantity whereas distance is scalar quantity.
Distance is the magnitude of displacement. Hence distance is always greater than or equal to displacement.
Option D is correct.

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A meteor is approaching Earth. Which statement about its motion is true?
Maslowich
B. The meteor accelerates
3 0
3 years ago
Read 2 more answers
1.
lyudmila [28]

Answer:

100m \div  \frac{9 \: m}{1sec}  = 11.11 \: sec \:

I guess you can round it to 11 seconds.

Explanation:

Going with a speed 9m/s means you are going 9 meters in each second.

If you are going 9 meters in second how many seconds will it take to 100 meters?

Visually;

9 meters - - - 1 second

100 meters - - - ?seconds.

When you write like this 9 times ?seconds equal to 100 meters time 1 second. (you probably know this but just in case)

So to find ?second you multiply 100meters by 1 and divide it by 9 whixh will give you 11.1111 seconds whixh again I believe you can round it to 11.

(Kind of a) Proof;

If 9m * ?sec = 100 m * 1 sec

you send 9 meters to other side.

?sec = (100 m * 1 sec) ÷ 9m

Hope it was clear and it helps! Please let me know if you have any questions.

7 0
3 years ago
At 900.0 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2SO2(g)+O2(g)→2SO3(g) At equilibrium, the partial
elena55 [62]

Answer : The partial pressure of SO_3 is, 67.009 atm

Solution :  Given,

Partial pressure of SO_2 at equilibrium = 30.6 atm

Partial pressure of O_2 at equilibrium = 13.9 atm

Equilibrium constant = K_p=0.345

The given balanced equilibrium reaction is,

2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)

The expression of K_p will be,

K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2\times (p_{O_2})}

Now put all the values of partial pressure, we get

0.345=\frac{(p_{SO_3})^2}{(30.6)^2\times (13.9)}

p_{SO_3}=67.009atm

Therefore, the partial pressure of SO_3 is, 67.009 atm

6 0
3 years ago
Sometimes referred to as the law of inertia. An object at rest stays at rest and an object in motionstays in motion with the sam
Lera25 [3.4K]

Answer:

D

Explanation:

Newtons first law states that if an object is at rest it will stay at rest only if an unbalanced force acts on it. As well as if an object is in motion it will stay in motion unless an unbalanced force acts on it.

Ps- The object will stay moving in the same speed and direction.

5 0
3 years ago
block with of mass m is at rest on horizontal frictionless surface at time t=0. A force given by F=Bt+C is applied horizontally
Alexeev081 [22]

Answer:

v_{2} =\frac{1}{2}

Explanation:

From the second law of Newton movement laws, we have:

F=m*a, and we know that a is the acceleration, which definition is:

a=\frac{dv}{dt}, so:

F=m*\frac{dv}{dt}\\\frac{dv}{dt}=\frac{F}{m}=\frac{\frac{1}{2}(t+1)}{4}=\frac{t+1}{8}

The next step is separate variables and integrate (the limits are at this way because at t=0 the block was at rest (v=0):

dv=\frac{1}{8}(t+1)dt\\\int\limits^{v_{2}}_0 \, dv=\int\limits^{2}_{0} {\frac{1}{8}(t+1)} \, dt

v_{2}=\frac{1}{8}*(\frac{t^{2}}{2}+t) (This is the indefinite integral), the definite one is:

v_{2}=\frac{1}{8}*(2+2)=\frac{1}{2}

3 0
3 years ago
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