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3 years ago

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A bullet of mass 0.010 kg and speed of 200 m/s is brought to rest in a wooden block after penetrating a distance of 0.10 m. The

work done on the bullet by the block is

1 answer:

irina [24]3 years ago

7 0

Answer:

W = 200 J

Explanation:

Work will be equal to the change in kinetic energy

W = ½mv² - 0

W = ½(0.010)200²

W = 200 J

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Explanation:

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A solenoid coil with 22 turns of wire is wound tightly around another coil with 330 turns. The inner solenoid is 21.0 cm long an

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Answer:

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Explanation:

Given that,

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Diameter = 2.30 cm

Current in inner solenoid = 0.140 A

Rate = 1800 A/s

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We need to calculate the magnetic flux

Using formula of magnetic flux

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Hence, The average magnetic flux through each turn of the inner solenoid is $11.486\times10^{-8}\ Wb$

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