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valentinak56 [21]
3 years ago
11

What structures are found in plant cells that are not what structures are found in plant cells that are not me found in animal c

ells
Chemistry
1 answer:
Amanda [17]3 years ago
3 0

Special Structures in Plant Cells. Most organelles are common to both animal and plant cells. However, plant cells also have features that animal cells do not have: a cell wall, a large central vacuole, and plastids such as chloroplasts.

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Pure metals tend to be weaker and more reactive than an alloy which is a
Alex17521 [72]
Alloys are supposed to give greater strength to metals, which is why gold is mixed with others to make it harder. They have greater strength and are more resistant to erosion.
5 0
3 years ago
HNO3 + H2SO4 + NO
77julia77 [94]

Explanation:

The two half equations are;

3e + HNO3 → NO

S→ H2SO4 + 6e

When balancing half equations, we have to make sure the number of electrons gained is equal to the number of electrons lost.

<em>Which factor will you use for the top equation?</em>

We multiply by 2 to make the number of electrons =  6e

<em>Which factor will you use for the bottom equation?</em>

We multiply by 1 to make the number of electrons = 6e

3 0
2 years ago
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
a_sh-v [17]

Answer:

m_{H_2O}=39.0g

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g

Best regards.

8 0
3 years ago
(01.04 MC)
iogann1982 [59]
I turned in this exact assignment today haha

the blood vessels dilate to draw body heat away from the body and towards the surface of the skin
sweat glands release sweat, when sweat evaporates it releases heat
6 0
3 years ago
If you double the volume of a sample of gas and then doubled the volume again without changing its pressure, how would this abso
IRINA_888 [86]

Answer:

Explanation:

Increasing Volume while maintaining constant pressure requires a proportional increase in Temperature so the gas pressure will be maintained as constant.

Consider...

V₁ = V₁     V₂ = 4V₁

T₁ = T₁      T₂ = ?

Charles Law => T ∝ V at constant P ... that is, increasing temperature generates a proportional increase in volume to maintain constant pressure.

Empirical Charles Law Relation is ...

V₁/T₁ = V₂/T₂ => T₂ = T₁(V₂/V₁) = T₁(4V₁/V₁) = 4T₁

Increasing Volume of a gas by 4 times requires a 4 times increase in absolute temperature in order to maintain constant pressure.

7 0
3 years ago
Read 2 more answers
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