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algol13
4 years ago
10

How many grams of hydrochloric acid and required to react completely with 61.8 grams of calcium hydroxide when they produce calc

ium chloride and water?
Chemistry
1 answer:
Keith_Richards [23]4 years ago
7 0
2HCl+Ca (OH)2------>cacl2+2H2O
...now every 2 moles of hcl reacts with 1 mole ca (oh)2.....
2moles of hcl = 2×(36.5)=73 gm..
1 mole of ca (oh)2=40+(17×2)=74 gm..
so ... 61.8 gm of hcl need ...(61.8×73)/74= 60.964864864
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Answer:

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Explanation:

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From the table above AgNO₃ is the limiting reagent and we will produce 0.10 mol AgCl which is a mass :

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5 0
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Semmy [17]

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6 0
4 years ago
Read 2 more answers
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