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IgorC [24]
3 years ago
13

A solution of 0.2 M Sulfuric acid is titrated with a 0.2 M basic solution. In three to five sentences, explain how you can use t

he results of the titration as evidence for the ratio of sulfuric acid and the base in the balanced chemical reaction for the titration.
Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
5 0

If there are 0.2 M solutions of both acid and base, the concentrations of hydrogen and hydroxide ions will be equal at equivalence point.

The reaction of sulfuric acid and a basic solution BOH occurs as follows;

H2SO4(aq) + 2BOH(aq) -----> B2SO4(aq) + 2H2O(l)

In the question, we are told that that both the solution of the sulfuric acid and the basic solution are 0.2 M.

The point where all the hydrogen and hydroxide ions have reacted according to the stoichiometry of the reaction. If there is really equimolar amounts of acid and base, the concentration of hydrogen and hydroxide ions will be equal at equivalence point.

Learn more: brainly.com/question/2192784

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Answer:

Mole fraction H₂O → 0.72

Mole fraction C₂H₅OH → 0.28

Explanation:

By the mass of the two elements in the solution, we determine the moles of each:

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25 g . 1 mol / 46 g = 0.543 moles of ethanol (solvent)

Mole fraction solute = Moles of solute / Total moles

Mole fraction solvent = Moles of solvent / Total moles

Total moles = Moles of solute + Moles of solvent

1.39 moles of solute + 0.543 moles of solvent = 1.933 moles → Total moles

Mole fraction H₂O = 1.39 / 1.933 → 0.72

Mole fraction C₂H₅OH= 0.543 / 1.933 → 0.28

Remember that sum of mole fractions = 1

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