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ahrayia [7]
3 years ago
11

1. What volume of toluene do you need to add to 1 mL of ethyl acetate to make an equi-molar mixture? The density of ethyl acetat

e (C4H8O2) is 0.898 g/mL and the density of toluene (C7H8) is 0.867 g/mL.
Chemistry
1 answer:
galben [10]3 years ago
4 0

Answer:

1.06 mL of toluene will be needed.

Explanation:

Equi-molar mixture means equal moles of all the components.

as given the volume of ethyl acetate = 1mL

Density of ethyl acetate = 0.898 g/mL

The relation between density, mass and volume is :

density=\frac{mass}{volume}

mass=volumeXdensity

mass of ethyl acetate present = 1mL X 0.898g/mL = 0.598 grams

the moles are related to mass as:

moles=\frac{mass}{molarmass}

For ethyl acetate molar mass = 4X12+8X1+2X16= 88g/mol

moles of ethyl acetate will be:

moles=\frac{0.898}{88}= 0.01mol

So we need 0.01 moles of toluene also

For 0.01 moles the mass of toluene required = 0.01 X molar mass of toluene

mass required = 0.01 X 92=0.92grams

for 0.92 grams of toluene volume required will be:

volume=\frac{mass}{density}=\frac{0.92}{0.867}= 1.06mL

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4 years ago
At 25 ∘C , the equilibrium partial pressures for the reaction were found to be PA=5.16 bar, PB=5.04 bar, PC=4.11 bar, and PD=4.8
erastova [34]

Answer: 5.85kJ/Kmol.

Explanation:

The balanced equilibrium reaction is

A(g)+2B(g)\rightleftharpoons 4C(g)+D(g)

The expression for equilibrium reaction will be,

K_p=\frac{[p_{D}]\times [p_{C}]}^4{[p_{B}]^2\times [p_{A}]}

Now put all the given values in this expression, we get the concentration of methane.

K_p=\frac{(4.85)\times [(4.11)^4}{(5.04)^2\times (5.16)}

K_p=10.6

Relation of standard change in Gibbs free energy and equilibrium constant is given by:

\Delta G^o=-2.303\times RT\times \log K_c

where,

R = universal gas constant = 8.314 J/K/mole

T = temperature = 25^0C=(25+273)K=298 K

K_c = equilibrium constant = 10.6

\Delta G^o=-2.303\times 8.314\times 298\times \log (10.6)

\Delta G^o=5850.23J/Kmol

\Delta G^o=5.85kJ/Kmol

Thus standard change in Gibbs free energy of this reaction is 5.85kJ/Kmol.

3 0
3 years ago
What is the value of the equilibrium constant at 25 oC for the reaction between the pair: Ag(s) and Ni2+(aq) to give Ni(s) and A
rusak2 [61]

Answer: 3\times 10^{35}

Explanation:

The balanced chemical equation will be:

2Ag(s)+Ni^{2+}(aq)\rightarrow 2Ag^{+}(aq)+Ni(s)

Here Ag undergoes oxidation by loss of electrons, thus act as anode. Nickel undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0_{[Ag^{+}/Mg]}=+0.80V

E^0_{[Ni^{2+}/Ni]}=-0.25V

E^0=E^0_{[Ni^{2+}/Ni]}- E^0_{[Ag^{+}/Ag]}

E^0=-0.25-(+0.80V)=-1.05V

The standard emf of a cell is related to Gibbs free energy by following relation:

\Delta G=-nFE^0

\Delta G = gibbs free energy  

n= no of electrons gained or lost  =?

F= faraday's constant

E^0 = standard emf

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The Gibbs free energy is related to equilibrium constant by following relation:

\Delta G=-2.303RTlog K

R = gas constant = 8.314 J/Kmol

T = temperature in kelvin =25^0C=25+273=298K

K = equilibrium constant

\Delta G=-2.303RTlog K

+202650=-2.303\times 8.314\times 298\times logK

K=3\times 10^{35}

Thus the value of the equilibrium constant at 25^0C is 3\times 10^{35}

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Answer:

IT IS D because lights are heated and it gives light!

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3 years ago
Which of the following fractions can be used in the conversion of 25 m3 to the unit cm3?
zaharov [31]

your answer would be C hope this helps

8 0
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