3 years ago

Each cement block weighs 1 1/4 how much do 8 cement blocks weigh

Mathematics

1 answer:

vladimir1956 [14]3 years ago

3 0

Answer:

Step-by-step explanation:

(1 1/4) * 8 = 10

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2. The Citadel's current enrollment is 1200 students. The enrollment is predicted to

Lynna [10]

Answer:

Step-by-step explanation:

hey

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3 years ago

PLEASE HELP WILL GIVE BRAINLIEST

Naily [24]

Y=-5x -2 should be the equation I’ll go check tho

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2 years ago

You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

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2 years ago

Catherine is a sixth grader at her school. The sixth graders are collecting food items to donate to the local shelter. Their goa

Goryan [66]

Answer:A= 7

Step-by-step explanation:

y=mx+b

512=114x+134

subtract 134 from both sides of the equation,

378=114x

Divide 144 from both sides of the equation to get x by itself

x=6.25

you'll round up because you can't really have a quarter day.

A= 7

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3 years ago

The points (3, 9) and (–3, –9) are plotted on the coordinate plane using the equation y = a • x.

marysya [2.9K]

The answer would be a=3

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2 years ago