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timama [110]
1 year ago
7

A water wave has a frequency of 6 Hz and a wavelength of 3 m. (a) What is the period of these waves? (b) What is the wave veloci

ty?
Physics
1 answer:
sladkih [1.3K]1 year ago
6 0

The period or time duration of these waves is 0.16 sec. While the wave velocity is 18m/sec.

<h3>What is Wavelength?</h3>

Wavelength may be defined as the space between equivalent points in the contiguous cycles of a waveform signal propagated in the area or along a wire.

The time duration of these waves is calculated by the given formula:

T = \frac{1}{F} = \frac{1}{6} = 0.16 seconds.

The velocity is calculated by the given formula:

V= Wavelength × Frequency = 6Hz × 3m = 18m/sec.

Therefore, it is well described above.

To learn more about wavelength and frequency, refer to the link:

brainly.com/question/10728818

#SPJ1

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If the distance between the charges is reduced to half,

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An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface char
ArbitrLikvidat [17]

Answer:

Part a)

W = 1.58 \times 10^{-20} J

Part b)

v = 1.86 \times 10^5 m/s

Explanation:

Part a)

Electric field due to large sheet is given as

E = \frac{\sigma}{2\epsilon_0}

\sigma = 4.00 \times 10^{-12} C/m^2

now the electric field is given as

E = \frac{4.00 \times 10^{-12}}{2(8.85 \times 10^{-12})}

E = 0.225 N/C

Now acceleration of an electron due to this electric field is given as

a = \frac{eE}{m}

a = \frac{(1.6 \times 10^{-19})(0.225)}{9.1 \times 10^{-31}}

a = 3.97 \times 10^{10}

Now work done on the electron due to this electric field

W = F.d

d = 0.470 - 0.03

d = 0.44 m

So work done is given as

W = (ma)(0.44)

W = (9.11 \times 10^{-31})(3.97 \times 10^{10})(0.44)

W = 1.58 \times 10^{-20} J

Part b)

Now we know that work done by all forces = change in kinetic energy of the electron

so we will have

W = \frac{1}{2}mv^2 - 0

1.58 \times 10^{-20} = \frac{1}{2}(9.1\times 10^{-31})v^2

v = 1.86 \times 10^5 m/s

7 0
3 years ago
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