The answer to your question I think it is A but I’m not 100%
Answer:
a)3.86 ×10³m/s
b)4.83× 10⁷ s
Explanation:
a)
The speed that a satellite at a given radius must travel so as to orbit in the presence of gravity is given by;
where;
G is the universal gravitational constant given as 6.67 × 10⁻¹¹ N.m²/kg²
m is mass of Earth given as 5.972×10²⁴kg
r is the radius at which the satellites orbit
v is the speed of satellite
r is obtained by the sum of distance from center of Earth and height of satellite from earth
Height of satellite from earth= 11000 nautical miles
1 nautical mile=1.852 km
11000 nautical miles =?
11000*1.852 = 20372 km
1 km = 1000 m
20372 km=?
=20372000m
=2.04×10⁷ m
r= 6.38×10⁶ m +2.04×10⁷ m
r=2.68×10⁷ m
Substitute values in equation;
b)The formula for period is
where T is the period of the satellite
Substituting values
Answer:
D may likely be your answer
99.0km/h =27.5m/s (this is the initial speed)
The final speed is zero
The distance is 50.0m
Therefore you use the formula:
vfinal²=vinitial²+2ad
a=(vfinal²-vinitial²)/2d
= (0²-27.5²)/(2x50.0)
=-7.5625 or in correct sigdigs -7.56m/s²
Hope this helps!
Answer:
16.6 kJ/°C
Explanation:
given,
Amount of heat absorbed = 45 kJ
initial temperature, T₁ = 25.5°C
final temperature, T₂ = 28.2°C
change in temperature = T₂ - T₁
= 28.2 - 25.5 = 2.7° C
Heat capacity of the object is equal to 16.6 kJ/°C