0.5 kg air hockey puck is initially at rest. What will it’s kinetic energy be after a net force of .8 N acts on it for a distanc
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Answer:
<em>radius of the loop = 7.9 mm</em>
<em>number of turns N ≅ 399 turns</em>
Explanation:
length of wire L= 2 m
field strength B = 3 mT = 0.003 T
current I = 12 A
recall that field strength B = μnI
where n is the turn per unit length
vacuum permeability μ = = 1.256 x 10^-6 T-m/A
imputing values, we have
0.003 = 1.256 x 10^−6 x n x 12
0.003 = 1.507 x 10^-5 x n
n = 199.07 turns per unit length
for a length of 2 m,
number of loop N = 2 x 199.07 = 398.14 ≅ <em>399 turns</em>
since there are approximately 399 turns formed by the 2 m length of wire, it means that each loop is formed by 2/399 = 0.005 m of the wire.
this length is also equal to the circumference of each loop
the circumference of each loop =
0.005 = 2 x 3.142 x r
r = 0.005/6.284 = = 0.0079 m =<em> 7.9 mm</em>
The displacement is 2 m south
Explanation:
Distance and displacement are two different quantities:
- Distance is the total length of the path covered by an object during its motion, regardless of the direction. It is a scalar quantity
- Displacement is a vector connecting the initial position to the final position of motion of an object. The magnitude of the displacement is the distance in a straight line between the two points
For the car in this problem, the motion is:
10 m south
8 m north
Taking north as positive direction, we can describe the two parts of the motion as
m
Therefore, the final position of the car with respect to the original position is
which means 2 m south: so, the displacement of the car is 2 m south.
Learn more about distance and displacement:
#LearnwithBrainly
Answer:
B= -6.0×10⁻⁴J
Explanation:
FIND THE SOLUTION BELOW
