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3 years ago

12

0.5 kg air hockey puck is initially at rest. What will it’s kinetic energy be after a net force of .8 N acts on it for a distanc

e of 2 m

1 answer:

weqwewe [10]3 years ago

4 0

Answer:

1.6 J

Explanation:

Work = change in energy

W = ΔKE

Fd = KE

(0.8 N) (2 m) = KE

KE = 1.6 J

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Simplify the expression [9+2(2-4)]/3

il63 [147K]

Answer:

5/3

Explanation:

[9+2(2-4)]/3

BODMAS

[9+2(-2)]/3

[9-4]/3

5/3

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3 years ago

how many paths through which charge can flow would be shown in a circuit diagram of a series circuit? a. one b. two or more c. n

katrin [286]

A series circuit is one in which there is only one path for current to follow.

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3 years ago

Read 2 more answers

I NEEEED HELPPPPPPP PLEASEEEE

monitta

Answer:

Below

Explanation:

1) To find the average velocity of an object you can use this formula :

v = ∆displacement / ∆time

v = 200 m / 5 s

v = 40 m/s

The average velocity of the turtle is 40 m/s

2) To find the distance an object can travel you can use this formula :

d = (∆velocity)(∆time)

d = (20m/s)(5s)

d = 100 m

The cheetah can run 100 meters in 5 seconds

3) To find the amount of time it takes for an object to move :

t = ∆displacement / ∆velocity

t = 5mi / 20 mph

t = 0.25 h

It would take this car 0.25 h to travel 5 miles at 20 mph

4) To find how far an object can go :

d = (∆velocity)(∆time)

d = (20mph)(3h)

d = 60 mi

The car can drive 60 miles driving 20 mph for 3 hours

5) To find how far an object can go :

d = (∆velocity)(∆time)

d = (20mph)(30min)

d = (20mph)(0.5h)

d = 10 mi

The car can drive 10 miles driving 20mph for 30 minutes

6) To find how long it would take :

t = ∆displacement / ∆velocity

t = 10 m / 50 m/s

t = 0.2 s

It would take the train 0.2 seconds for a train to travel 10 m at 50 m/s

7) To find how far :

d = (∆velocity)(∆time)

d = (670,000,000 mph)(1 yr)

d = (670,000,000 mph)(8760 h)

d = 5869200000000 mi

1 light year is 5869200000000 miles

Hope this helps! Best of luck <3

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3 years ago

While online last week, you saw the following advertisement:

Karolina [17]

No scientific testing has been made to check for ion transfer, and the claims are purely empirical. Also, nine out of ten people is hardly a representative sample, and the people can claim whatever they want since "feeling" is subjective. This is most likely a pseudoscientific claim, made to sound legitimate to consumers. The best answer is choice D.

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3 years ago

Read 2 more answers

A 69.5-kg person throws a 0.0475-kg snowball forward with a ground speed of 31.5 m/s. A second person, with a mass of 57.5 kg, c

Leno4ka [110]

Answer:

- After throwing the snow, velocity of the thrower is 2.33 m/s

- the velocity of the receiver is 0.026 m/s

Explanation:

Given the data in the question;

Using conservation of momentum,

Initial thrower has a momentum of mv; $m_{total$ v

(69.5 kg + 0.0475 kg) × 2.35 m/s = 163.4366 kg.m/s

Now, When he throws it at 31.5 m/s, these constitutes a momentum of;

(0.0475 kg )(31.5 m/s) = 1.49625 kg.m/s

hence his momentum now is: 163.4366 - 1.49625 = 161.94035 kg.m/s

To get his velocity, we say;

161.94035 = mv

{ he lost weight of the snow ball so, m = 69.5 kg )

161.94035 = 69.5 × v

v = 161.94035 / 69.5

v = 2.33 m/s

Therefore, After throwing the snow, velocity of the thrower is 2.33 m/s

Next is the Receiver;

the receiver will gain momentum of 1.49625 kg.m/s

he has no momentum initially and after he catches the snow ball;

1.49625 kg.m/s = mv

1.49625 kg.m/s = ( 57.5 kg + 0.0475 kg ) × v

1.49625 kg.m/s = 57.5475 kg × v

v = ( 1.49625 kg.m/s ) / 57.5475 kg

v = 0.026 m/s

Therefore, the velocity of the receiver is 0.026 m/s

3 0

3 years ago