Answer:
A
B
Explanation:
From the question we are told that
The wavelength is 
The angle of first bright fringe is 
The order of the fringe considered is n =1
Generally the condition for constructive interference is
=> 
=> 
Converting to cm
Generally the number of grating pre centimeter is mathematically represented as
=> 
=>
Considering question B
From the question we are told that
The first wavelength is 
The second wavelength is 
The order of the fringe is 
The grating is 
Generally the slit width is mathematically represented as
=> 
=> 
Generally the condition for constructive interference for the first ray is mathematically represented as
=> ![\theta_1 = sin^{-1} [\frac{ 2 * \lambda }{d}]](https://tex.z-dn.net/?f=%5Ctheta_1%20%3D%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B%202%20%2A%20%20%5Clambda%20%7D%7Bd%7D%5D)
=> ![\theta_1 = sin^{-1} [\frac{ 2 * 650 *10^{-9} }{ 2*10^{-6}}]](https://tex.z-dn.net/?f=%5Ctheta_1%20%3D%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B%202%20%2A%20%20%20650%20%2A10%5E%7B-9%7D%20%7D%7B%202%2A10%5E%7B-6%7D%7D%5D)
=> 
Generally the condition for constructive interference for the second ray is mathematically represented as
=> ![\theta_2 = sin^{-1} [\frac{ 2 * \lambda_1 }{d}]](https://tex.z-dn.net/?f=%5Ctheta_2%20%3D%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B%202%20%2A%20%20%5Clambda_1%20%7D%7Bd%7D%5D)
=> ![\theta_2 = sin^{-1} [\frac{ 2 * 420 *10^{-9} }{ 2*10^{-6}}]](https://tex.z-dn.net/?f=%5Ctheta_2%20%3D%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B%202%20%2A%20%20%20420%20%2A10%5E%7B-9%7D%20%7D%7B%202%2A10%5E%7B-6%7D%7D%5D)
=> 
Generally the angular separation is mathematically represented as
=> 
=>
It is a chemical change and a physical change
Answer:
6.39 J of energy is needed to generate 0.71 * 10⁻¹⁶ kg mass
Explanation:
According to the Equation: E = mc²
where the mass, m = 0.71 * 10⁻¹⁶ kg
the speed of light, c = 3 * 10⁸ m/s
The amount of energy needed to generate a mass of 0.71 * 10⁻¹⁶ kg is calculated as follows:
E = (0.71 * 10⁻¹⁶) (3 * 10⁸)²
E = 0.71 * 10⁻¹⁶ * 9 * 10¹⁶
E = 0.71 * 9
E = 6.39 J
The correct answer is the Type of batteries
Explanation:
In an experiment, it is normal the researcher modifies one variable, in this case, the number of batteries (independent variable), and this variable affects the variable tested, in this case, the brightness of the bulb (dependent variable).
However, other factors or variables should be constant to guarantee the results are reliable. In this context, one factor that the student should keep constant is the type of batteries he uses because this is not one of the main variables and therefore it is not expected he changes this on purpose or this is affected by other variables. Moreover, by making any change the experiment can be negatively affected. For example, batteries might differ in their power capacity this can affect the brightness of the bulbs.
Answer:
3N not 0N (first blank)
3N (second blank)
0N (third blank)
Explanation:
1st blank - If a force equals 0, it is balanced.
2nd blank - If one force of 3 Newtons is pushing to the left and another force of 3 Newtons is pushing from the right it wouldn't go anywhere, so it would be balanced at zero.
3rd blank - It would be 0N because forces of the same amount pushing opposite directions would be balanced.
