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myrzilka [38]
3 years ago
15

When you see yourself in a plane mirror, the image is always:

Physics
1 answer:
Charra [1.4K]3 years ago
6 0
It’s c “ the same size as you are”
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True or False?
WINSTONCH [101]

Answer:

true is the answer of the question

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3 years ago
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a nonrelativistic proton is confined to a length of 2.0 pm on the x-axis. what is the kinetic energy of the proton if its speed
Elina [12.6K]

Answer:

K = 1.29eV

Explanation:

In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:

\Delta x \Delta p\geq \frac{h}{4\pi}      (1)

Δx : uncertainty of position = 2.0pm = 2.0*10^-12m

Δp: uncertainty of momentum = ?

h: Planck's constant = 6.626*10^-34 J.s

You calculate the minimum possible value of Δp from the equation (1):

\Delta p=\frac{h}{4\pi \Delta x}=\frac{6.626*10^{-34}J.s}{4\pi(2.0*10^{-12}m)}\\\\\Delta p=2.63*10^{-23}kg.\frac{m}{s}

The minimum kinetic energy is calculated by using the following formula:

k=\frac{(\Delta p)^2}{2m}       (2)

m: mass of the proton = 1.67*10^{-27}kg

k=\frac{(2.63*10^{-23}kgm/s)^2}{2(1.67*10^{-27}kg)}=2.08*10^{-19}J

in eV you have:

2.08*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.29eV

The kinetic energy of the proton is 1.29eV

7 0
3 years ago
you stretch a spring by a distance of 0.3 m. the spring has a spring constant of 440 n/m. when you release the spring, it snaps
Alina [70]

Answer:

19.8 J

Explanation:

According to the law of conservation of energy, the total mechanical energy of the spring (sum of kinetic energy and elastic potential energy) must be conserved:

K_i + U_i = K_f + U_f (1)

where we have

K_i is the initial kinetic energy of the spring, which is zero because the spring starts from rest (2)

U_i is the elastic potential energy of the spring when it is fully stretched

K_f is the kinetic energy of the spring when it reaches the natural length

U_f is the elastic potential energy of the spring when it reaches its natural length, which is zero because the stretch in this case is zero (3)

So

U_i = \frac{1}{2}k(\Delta x_i)^2

where

k = 440 N/m is the spring constant

\Delta x_i = 0.3 m is the initial stretching of the spring

Substituting,

U_i = \frac{1}{2}(440)(0.3)^2=19.8 J

And so using eq.(1) and keeping in mind (2) and (3) we find

K_f= U_i = 19.8 J

8 0
3 years ago
How do you get smarter.... that's what brought me here...
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In a nuclear fusion reaction, what state is matter in?
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<span>the matter is in chemical <span>plasma
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<span>Alternatively d<span>)

</span></span>
<span>I hope I was helpfull

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3 years ago
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