Suatu tim basket memiliki 12 pemain.pelatih dapat membentuk variasi tim sebanyak?

1 answer:

5 0

12C5

$\frac{12!}{5!(12-5)!}= \frac{12!}{5!7!} = \frac{12\times 11 \times 10\times 9 \times 8}{5!} = 12\times 11\times 3 \times 2 = \huge{\boxed{\bf{792}}}}$

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A salad bar offers vegetable platters in 4 sizes (small, medium, large, and super-sized) and 6 different vegetables to choose fr

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Answer: She could create 60 platters.

Step-by-step explanation:

Given: A salad bar offers vegetable platters in 4 sizes (small, medium, large, and super-sized) and 6 different vegetables to choose from.

Number of combinations of selecting r things from n things is given by:-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

So, the number of combinations of selecting 2 different vegetables from 6 = $^6C_2=\dfrac{6!}{2!4!}=\dfrac{6\times5}{2}=15$

Now, By Fundamental counting principle, the number of different platters she could create = (number of ways of selecting 2 different vegetables from 6) x (Number of sizes)

= 15 x 4

= 60

Hence, she could create 60 platters.

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