Answer:
The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
Step-by-step explanation:
Let <em>X</em> = the number of miles Ford trucks can go on one tank of gas.
The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 350 miles and standard deviation, <em>σ</em> = 10 miles.
If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.
Compute the value of P (X < 325) as follows:

Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
Answer:
It is an arithmetic sequence and the common difference is 5
Step-by-step explanation:
4+5 = 9; 9+5=14 (adding is arithmetic, multiplying is geometric)
The maximum number of nights he could stay is 4 nights
Answer: The answer is of course, 3.
Step-by-step explanation:
I believe it is twenty eight. Ten is two thirds of fifteen. Twenty eight is two thirds of forty two. But I'm just assuming tbh