3 years ago

Can someone please answer this?

Mathematics

1 answer:

Finger [1]3 years ago

3 0

Answer:

if you need these worked out lmk hope this helps :)

Step-by-step explanation:

1.) infinite solutions

2.) infinite solutions

3.) x = .36923..

4.) no real solution

5.) no real solution

6.) x = 5

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Answer:

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Step-by-step explanation:

The range of a projectile is given by :

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Put R = 20 m, u = 15 m/s and finding the value of angle of projection

So,

$R=\dfrac{u^2\sin2\theta}{g}\\\\\sin2\theta=\dfrac{Rg}{u^2}\\\\\sin2\theta=\dfrac{20\times 9.8}{15^2}\\\\\sin2\theta=0.871\\\\2\theta=\sin^{-1}(0.871)\\\\2\theta=60.57\\\\\theta=30.285^{\circ}$

So, the required angle of projection is equal to $30.285^{\circ}$ .

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