We are given the equation:
13x^2 + 6√3 xy + 7y^2 - 16 = 0
Based on the general equation of conic sections:
Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0,
A = 13
B = 6√3
C = 7
D = 0
E = 0
F = -16
So we can find the graph of the equation by solving for the discriminate B^2 - 4AC
B^2 - 4AC, substitute given:
(6^2 * 3) - 4 (13 * 7) = -256
since the discriminate is less than zero, the graph could be a circle or a parabola. In this case, the values of A and C are not equal, then our graph is a parabola.
Answer:
y =6x+17
Step-by-step explanation:
First we need to find the slope
m = (y2-y1)/(x2-x1)
= (-7- -1)/(-4 - -3)
= (-7+1)/(-4+3)
-6/-1
6
The slope intercept form of the equation is
y = mx+b where m is the slope and b is the y intercept
y = 6x+b
Substitute a point into the equation
-1 = 6(-3) +b
-1 = -18+b
Add 18 to each side
17 =b
The equation is
y =6x+17
Answer:
33 days
Step-by-step explanation:
15 + 18 = 33
Hi there!
If the lines are parallel, Angles 1 and 2 would have to be congruent because they are corresponding angles. Therefore, to solve, all we need to do is set the values of the angles equal to each other because the angles are congruent.
WORK:
20 - 8x = 30 - 16x
-8x = 10 - 16x
8x = 10
x = 1.25
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:
DB = 8
Step-by-step explanation:
Δ ADB and Δ BDC are similar so ratios of corresponding sides are equal, that is
= 
, substitute values
= 
= ( cross- multiply )
DB² = 64 ( take the square root of both sides )
DB = 
= 8
