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3 years ago

12

The larger of two integers is 4 more than 9 times the smaller. The sum of the two integers is greater than or equal to 26. Find

the smaller possible integer values for both of these integers.

1 answer:

Westkost [7]3 years ago

8 0

Answer:

I think the equal number to 26 is 5 or mabye 2

Step-by-step explanation:

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Ipatiy [6.2K]

Answer:

1
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Step-by-step explanation

- 7(6x-1)+x=36

=> 42x - 7 + x = 36
=> 43x - 7 = 36
=> 43x = 36 + 6 = 43
=> x = 43 / 43 = 1

- 11-2(8+3p)=7²

=> 11 - 16 - 6p = 7^2
=> 11 - 16 - 6p = 49
=> -5 - 6p = 49
=> -6p = 49 + 5 = 54
=> p = (54) / (-6) = - 9

- 1/4(5b+11)=19

=> (5/4)b + (11/4) = 19
=> (5/4)b = 19 - (11/4) = 65 /4
=> b = (65/4) / (5/4) => (65/4) * (4/5) = 13

- 2/7(4m-18)=12

=> (8/7)m - (36/7) = 12
=> (8/7)m = 12 + (36/7) = 120/7
=> m = (120/7) / (8/7) = 120 /8 = 15

3 0

3 years ago