If there were 10 grams of a radioactive isotope, how much of the sample would be left after 1 half-life? How much after 2 half-l
1 answer:
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Answer:
sp³d¹ hybridization
Explanation:
Given Cl as central element with three F substrates ...
The VSEPR structure indicates 5 hybrid orbitals that contain 2 diamagnetic orbitals (non-bonded e⁻-pairs) and 3 paramagnetic orbitals (single, non-paired electron for covalent bonding with fluorine) giving a trigonal bypyrimidal parent with a T-shaped geometry.
Valence bond theory predicts the following during bonding:
Cl:[Ne]3s²3p²p²p¹3d⁰
=> [Ne]3s²p²p¹p¹d¹
=> [Ne]3(sp³d)²(sp³d)²(sp³d)¹(sp³d)¹(sp³d)¹
giving 3 ( [Cl](sp³d) - [F]2p¹ ) sigma bonds and 2 non-bonded pairs on Cl.
Note the following images:
Non-bonded electron pairs are in plane of parent geometry and Fluorides covalently bonded to central element Chloride forming the T-shaped geometry.
Answer:
<h2>0.52 g/mL</h2>Explanation:
The density of a substance can be found by using the formula
From the question
volume = final volume of water - initial volume of water
volume = 35 - 8 = 27 mL
We have
We have the final answer as
<h3>0.52 g/mL</h3>Hope this helps you