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Irina18 [472]
2 years ago
5

If there were 10 grams of a radioactive isotope, how much of the sample would be left after 1 half-life? How much after 2 half-l

ives?
Chemistry
1 answer:
Vikentia [17]2 years ago
3 0
One half-life: 5 grams
Two half-lives: 2.5 grams
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What reaction will take place if h2o is added to a mixture of nanh2/nh3? draw the products of the reaction (without sodium ion)?
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When sodium amide i.e.NaNH_{2} reacts with water i.e. H_{2}O results in the formation of sodium hydroxide i.e. NaOH and ammonia NH_{3}.

The chemical reaction is given by:

NaNH_{2}+H_{2}O\rightarrow NH_{3}+NaOH

Now, when ammonia i.e.NH_{3} reacts with water results in the formation of ammonium hydroxide i.e. NH_{4}OH

The chemical reaction is given by:

NH_{3}+H_{2}O\rightarrow NH_4OH

Thus, the products of the above reactions are ammonia and ammonium hydroxide (without sodium ion).

The structures of the products are shown in figure (1): ammonium hydroxide and figure (2) ammonia.


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3 years ago
The Kelvin scale is based on the concept of absolute zero.explain the concept
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3 years ago
How many molecules are there in 24 grams of FeF(3)?
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2 years ago
What has mass?<br> A. Energy<br> B. Heat<br> C. Light<br> D. Matter
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Read 2 more answers
A fuel tank holds 22.3 gallons of gasoline. If the density is 0.8206 g/mL, what is the mass in kilograms of gasoline in a full t
7nadin3 [17]

Answer:

m=69.3kg

Explanation:

Hello!

In this case, since the density is computed by dividing the mass of the substance by its occupied volume (d=m/V), we first need to realize that 0.8206 g/mL is the same to 0.8206 kg/L, which means we first need to compute the volume in L:

V=22.3gal*\frac{3.78541L}{1gal}=84.415L

Then, solving for the mass in d=m/V, we get m=d*V and therefore the mass of gasoline in that full tank turns out:

m=0.8206g/L*84.415L\\\\m=69.3kg

Best regards!

8 0
3 years ago
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