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garri49 [273]
2 years ago
9

The addition of an inert gas has no effect on the equilibrium position of a gaseous reaction because ______. Multiple choice que

stion. the inert gas has no effect on the equilibrium system at all since it is not involved in the reaction the partial pressures of the reaction components remain the same the reaction quotient compensates for the inert gas the total pressure of the system remain the same
Chemistry
1 answer:
boyakko [2]2 years ago
5 0

Inert gas does not affect the equilibrium position:

It is because the partial pressures of the reaction components remain the same.

What is Inert Gas?

  • Under a given set of conditions, an inert gas is a gas that does not undergo chemical reactions.
  • The noble gases (helium, neon, argon, krypton, xenon, and radon) were previously known as "inert gases" due to their perceived lack of involvement in any biochemical processes.
  • Because inert gases are non-reactive, they do not affect equilibrium partial pressures and thus do not affect volume.
  • An inert gas does not react with the reactants or products; it does not change the concentration of the products and reactants. Furthermore, because the volume is constant, the concentrations are unaffected. As a result, this does not affect equilibrium.

The equilibrium position won't change if an inert gas is added. A volume change won't change the equilibrium position if the total moles of gas in the products and reactants are the same. When the volume is reduced, the process changes to create fewer moles of gas.

Learn more about the inert gas here,

brainly.com/question/15909389

#SPJ4  

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Consider the complete reaction of 43.0 g of silicon with excess nitrogen gas in the reaction shown below. What mass of product f
kupik [55]
The answer to your question is : no.of moles of Si = 43/atomic mass of Si = 43/28.1 = 1.53

according to reaction 3 moles of Si gives 1 mole of Si3N4

so 1.53 mole of Si will give 1.53/3 = 0.51 mole of Si3N4

molar mass of Si3N4 = 140.28 g/mole

it means that 1 mole of Si3N4 = 140.28 g

so 0.51 mole of Si3N4 = 0.51 X 140.28 = 71.543 g
7 0
3 years ago
A molecule contains 23.24 g iodine (I),
gavmur [86]
Convert each amount of grams into moles:

I: 23.24g x 1 mol / 126.90g = 0.1831 mol I

C: 2.198 x 1 mol / 12.01g = 0.1830 mol C

N: 2.562 x 1 mol / 14.01g = 0.1829 mol N

Each element has roughly the same amount of moles, which means the whole number ratio between the elements is 1:1:1

Therefore the empirical formula is ICN
7 0
3 years ago
THURSDAY Mr. Pate's science class performed an experiment involving the chemical reaction of sodium bicarbonate (baking soda) an
Kitty [74]

The balloon will burst if the volume of the balloon is less than 1.68 L since 8 g of sodium bicarbonate produces 1.68 L of carbon dioxide gas.

<h3>What is the volume of carbin dioxude produced from the chemical reaction between sodium bicarbonate (baking soda) and vinegar?</h3>

The volume of carbon dioxide produced is obtained from the equation below:

CH_3COOH + NaCO_3 \rightarrow CH_3COONa + H_2O + CO_2 \\

1 mole of sodium bicarbonate reacts with one mole of acetic acid in vinegar to produce 1 mole of carbon dioxide.

The volume of 1 mole of carbon dioxide is 22.4 L

Moles of sodium bicarbonate in 8 g = mass/molar mass

molar mass of sodium bicarbonate = 106 g

moles of sodium bicarbonate = 8/106 = 0.075 moles

Moles of carbon dioxide produced = 0.075 moles

Volume of carbon dioxide = 0.075 × 22.4 = 1.68 L

Therefore, the balloon will burst if the volume of the balloon is less than 1.68 L.

Learn more about gas volume at: brainly.com/question/24263739

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7 0
2 years ago
When a sulfur atom gains its valence electrons to have 8, the charge on the resulting ion is
nikklg [1K]
<span>When a sulfur atom gains its valence electrons to have 8, the charge on the resulting ion is stable since sulfur atom achieved the octet rule. An octet rule is the filling of 8 electrons in an atom.</span>
8 0
3 years ago
Lead (II) chloride (PbCl2) has a Ksp of 1.17 x 10-5. Calculate the molar solubility of PbCl2, in moles per liter. Enter your ans
bixtya [17]

Answer:

1.43 * 10^-2

Explanation:

Firstly, we need to get the ionization equation for lead I chloride. We can then get the Initial, change and equilibrium table of the lead and chloride ions that can help us calculate the molar solubility. This is shown as follows:

PbCl2(s) --> Pb2+(aq) + 2 Cl-(aq)

This shows that one mole of lead ii chloride will yield 1 mole of the lead ion and 2 moles of the chloride ion.

The ICE table is shown below:

Pb2+ 2Cl-

Initial 0.00 0.00

Change +s +2s

Equilibrium s 2s

Ksp = [Pb2+][Cl-]^2

Ksp = [s][2s]^2

Ksp = 4s^3

s^3 = Ksp/4

s = cube.root [Ksp/4]

s = cube.root[1.17 * 10^-5/4]

s = 1.43 * 10^-2

3 0
3 years ago
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