The answer to your question is : no.of moles of Si = 43/atomic mass of Si = 43/28.1 = 1.53
according to reaction 3 moles of Si gives 1 mole of Si3N4
so 1.53 mole of Si will give 1.53/3 = 0.51 mole of Si3N4
molar mass of Si3N4 = 140.28 g/mole
it means that 1 mole of Si3N4 = 140.28 g
so 0.51 mole of Si3N4 = 0.51 X 140.28 = 71.543 g
Convert each amount of grams into moles:
I: 23.24g x 1 mol / 126.90g = 0.1831 mol I
C: 2.198 x 1 mol / 12.01g = 0.1830 mol C
N: 2.562 x 1 mol / 14.01g = 0.1829 mol N
Each element has roughly the same amount of moles, which means the whole number ratio between the elements is 1:1:1
Therefore the empirical formula is ICN
The balloon will burst if the volume of the balloon is less than 1.68 L since 8 g of sodium bicarbonate produces 1.68 L of carbon dioxide gas.
<h3>What is the volume of carbin dioxude produced from the chemical reaction between sodium bicarbonate (baking soda) and vinegar?</h3>
The volume of carbon dioxide produced is obtained from the equation below:

1 mole of sodium bicarbonate reacts with one mole of acetic acid in vinegar to produce 1 mole of carbon dioxide.
The volume of 1 mole of carbon dioxide is 22.4 L
Moles of sodium bicarbonate in 8 g = mass/molar mass
molar mass of sodium bicarbonate = 106 g
moles of sodium bicarbonate = 8/106 = 0.075 moles
Moles of carbon dioxide produced = 0.075 moles
Volume of carbon dioxide = 0.075 × 22.4 = 1.68 L
Therefore, the balloon will burst if the volume of the balloon is less than 1.68 L.
Learn more about gas volume at: brainly.com/question/24263739
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<span>When a sulfur atom gains its valence electrons to have 8, the charge on the resulting ion is stable since sulfur atom achieved the octet rule. An octet rule is the filling of 8 electrons in an atom.</span>
Answer:
1.43 * 10^-2
Explanation:
Firstly, we need to get the ionization equation for lead I chloride. We can then get the Initial, change and equilibrium table of the lead and chloride ions that can help us calculate the molar solubility. This is shown as follows:
PbCl2(s) --> Pb2+(aq) + 2 Cl-(aq)
This shows that one mole of lead ii chloride will yield 1 mole of the lead ion and 2 moles of the chloride ion.
The ICE table is shown below:
Pb2+ 2Cl-
Initial 0.00 0.00
Change +s +2s
Equilibrium s 2s
Ksp = [Pb2+][Cl-]^2
Ksp = [s][2s]^2
Ksp = 4s^3
s^3 = Ksp/4
s = cube.root [Ksp/4]
s = cube.root[1.17 * 10^-5/4]
s = 1.43 * 10^-2