Complete Question
Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in n=4 and the atom emits a photon of light with a wavelength of 486 nm. Group of answer choices
Answer:
Explanation:
From the question we are told that:
Wavelength 
Generally the equation for Atom Transition is mathematically given by
Where
Rydberg constant 
Therefore
Answer: 13.888g
Explanation:
CaCO3 —> CaO + CO2
From the equation above, 1mole of CaCO3 produces 1mole of CaO. Since the answer is to be expressed in grams, let us covert this mole to grams. This is illustrated below:
MM of CaCO3 = 40 +12 + (16x3) = 40 + 12 + 48 = 100g/mol
MM of CaO = 40 + 16 = 56g/mol
From the equation,
100g of CaCO3 produced 56g CaO
Therefore, 24.8g of CaCO3 will produce Xg of CaO i.e
Xg of CaO = (24.8 x 56) / 100 = 13.888g
Therefore, the theoretical yield of CaO is 13.888g
Data Given:
Pressure = P = ?
Volume = V = 3.0 L
Temperature = T = 115 °C + 273 = 388 K
Mass = m = 75.0 g
M.mass = M = 44 g/mol
Solution:
Let suppose the Gas is acting Ideally. Then According to Ideal Gas Equation,
P V = n R T
Solving for P,
P = n R T / V ------ (1)
Calculating Moles,
n = m / M
n = 75.0 g / 44 g.mol⁻¹
n = 1.704 mol
Putting Values in Eq. 1,
P = (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L
P = 18.08 atm
I think mass and atomic number
Answer:
They all have a hydrogen written separatly towards the beginning of the formula.
Explanation:
If you look at the Arrhenius acid formulas, you can see they all contain a hydrogen (H) at the beginning of them.
