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Eddi Din [679]
3 years ago
11

Please help me??? I'm so lost..

Chemistry
2 answers:
marishachu [46]3 years ago
7 0
B the brightness is the big and small waves 
Dahasolnce [82]3 years ago
3 0
The answer would be speed because brightness is how high the wave is and your trying to find the width. Also, you can't determine color from a wave like this
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How can we tell the distance sediments traveled due to erosion ?​
meriva

Answer:

more rounded the grains are the more they have been moved around

Explanation:

Generally – the more rounded the grains are the more they have been moved around (i.e. the longer the length of time or distance they have moved). Angular grains cannot have travelled far

geolsoc.org.uk

4 0
2 years ago
HELP I'LL GIVE YOU 15 POINTS CAUSE THAT'S ALL I'VE GOT, BUT I NEED IT PLEASE!
nekit [7.7K]

All mixtures contain only one kind of atom.

~Mschmindy

4 0
3 years ago
A transfer of heat within a liquid or gas that involves warm particles moving in currents is?
myrzilka [38]
It is called convection. When warm air, or current, moves up and disperse outwards as cold air, or current, moves into the warmer region.
3 0
3 years ago
Read 2 more answers
A 50.0 g sample of scandium, sc, is heated by exposure to 1.50 x 10 3 j. The temperature of the sc is raised by 61.1 o
statuscvo [17]

Given mass of Scandium = 50.0 g

Increase in temperature of the metal when heated = 61.1^{0}C

Heat absorbed by Scandium = 1.50*10^{3}J

The equation showing the relationship between heat, mass, specific heat and temperature change:

Q = m C (deltaT)

Where Q is heat = 1.50*10^{3}J

m is mass = 50.0 g

ΔT = 61.1^{0}C

On plugging in the values and solving for C(specific heat) we get,

1.50*10^{3}J=50.0g(C)(61.1^{0}C)

C = 0.491\frac{J}{g^{0}C }

Specific heat of the metal = 0.491\frac{J}{g^{0}C }

7 0
4 years ago
A certain gas is present in a 13.0 L cylinder at 1.0 atm pressure. If the pressure is increased to 2.0 atm , the volume of the g
Scorpion4ik [409]
<h3>Answer:</h3>

The gas obeys the Boyle's law

<h3>Explanation:</h3>
  • According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at constant absolute temperature.
  • That is; P\alpha\frac{1}{V}
  • Therefore, k=PV, where k is a constant
  • At varying volume and pressures while keeping absolute temperature constant; k = P1V1 =P2V2

In this case, we are given;

Initial Volume of 13.0 L at initial pressure of 1.0 atm

New volume of 6.5 L at new pressure of 2.0 atm

But, K = PV

Therefore,

k1 = P1V1

   = 1.0 atm × 13.0 L

  = 13 atm.L

k2 = P2V2

    = 2.0 atm × 6.5 L

    = 13 atm.L

Thus, k1=k2

Thus, the gas obeys the Boyle's law

8 0
3 years ago
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