Answer:
pCH4 = 0.9184 atm
pCCl4 = 0.9184 atm
pCH2Cl2 = 0.2832 atm
Explanation:
Step 1: Data given
The equilibrium constant, Kp= 9.52 * 10^-2
Temperature = 350 K
Each have an initial pressure of 1.06 atm
Step 2: The balanced equation
CH4(g) + CCl4(g) ⇆ 2CH2Cl2(g)
Step 3: The pressure at the equilibrium
pCH4 = 1.06 - X atm
pCCl4 = 1.06 - X atm
pCH2Cl2 = 2X
Step 4: Calculate Kp
Kp = (2X)² / (1.06 - X)*(1.06 - X)
9.52 * 10^-2 = 4X² / (1.06 - X)*(1.06 - X)
X = 0.1416
Step 5: Calculate the partial pressure
pCH4 = 1.06 - 0.1416 = 0.9184 atm
pCCl4 = 1.06 - 0.1416 = 0.9184 atm
pCH2Cl2 = 2 * 0.1416 = 0.2832 atm
Kp = (0.2832²) / (0.9184*0.9184)
Kp = 9.52 * 10^-2
pCH4 = 0.9184 atm
pCCl4 = 0.9184 atm
pCH2Cl2 = 0.2832 atm
Answer:
Mass of sample is 99.9 g, density of ample is 11.35
and temperature of sample is 
Explanation:
Mass is an additive property. Therefore mass of combined sample is summation of masses of two pellets.
Mass of combined sample = (37.2+62.7) g = 99.9 g
Density is an intensive property. Therefore density of combined sample of lead will be same as with density of Pb.
Density of combined sample = 11.35 
Temperature is an intensive property. Therefore temperature of combined sample of lead will be same as with individual pellets.
temperature of combined sample = 
Answer:
Explanation:some data are missing are they need experiment??
The boiling point would be measured as C) 373 Kelvin
These 2 isotopes are all of bromine that is naturally found (their percentages add up to 100%). In order to calculate the mean atomic mass, we can use the following calculation:

. This yields an average atomic mass of 79.903 amu. This procedure is general; whenever we have many types F of a specific genre G, the mean of the genre G can be calculated by:

where

is the proportion of type i in the genre G. In this example, Br79 and Br81 are the 2 types and the genre is Bromine.