A certain gas is present in a 13.0 L cylinder at 1.0 atm pressure. If the pressure is increased to 2.0 atm , the volume of the g as decreases to 6.5 L . Find the two constants ki, the initial value of k, and kf, the final value of k, to verify whether the gas obeys Boyle’s law.
1 answer:
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Answer: </h3>
The gas obeys the Boyle's law
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Explanation: </h3>
According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at constant absolute temperature. That is; Therefore, , where k is a constant At varying volume and pressures while keeping absolute temperature constant; k = P1V1 =P2V2 In this case, we are given;
Initial Volume of 13.0 L at initial pressure of 1.0 atm
New volume of 6.5 L at new pressure of 2.0 atm
But, K = PV
Therefore,
k1 = P1V1
= 1.0 atm × 13.0 L
= 13 atm.L
k2 = P2V2
= 2.0 atm × 6.5 L
= 13 atm.L
Thus, k1=k2
Thus, the gas obeys the Boyle's law
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