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Slav-nsk [51]
3 years ago
13

A transfer of heat within a liquid or gas that involves warm particles moving in currents is?

Chemistry
2 answers:
Alex777 [14]3 years ago
8 0
Convection.
Convection is the transfer of heat involving fluids (gas or liquids) with the heat rising cool sinking effect (lava lamp effect).
myrzilka [38]3 years ago
3 0
It is called convection. When warm air, or current, moves up and disperse outwards as cold air, or current, moves into the warmer region.
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The class of organic compound below contains a carbonyl group as a part of its structure?
kolbaska11 [484]

Aldehydes and Ketones. Aldehydes and ketones are classes of organic compounds that contain a carbonyl (C=O) group.

that's the correct answer

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5 0
3 years ago
Which of the following chemical equations proves that the law of conservation of mass is in effect?
bogdanovich [222]

Answer:

2KCl + F₂   →     2KF + Cl₂

Explanation:

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by French chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

2KCl + F₂   →     2KF + Cl₂

In this equation mass of reactant and product is equal. There are 2 potassium 2 chlorine and fluorine atoms on both side of equation it means mass remain conserved.

All other options are incorrect because mass is not conserved.

Mg₂ + LiBr ---> LiMg + Br

In this equation mass of magnesium is more on reactant side.

Na +O₂ ---> Na₂O

In this equation there is more oxygen and less sodium on reactant side while there is more sodium and less oxygen on product side.

H₂O ---> H₂ + O₂

In this equation there is less oxygen on reactant side while more oxygen on product side.

5 0
3 years ago
Stem cells can differentiate into how many types of body cells?
s2008m [1.1K]
There are two main types of stem cell: embryonic stem cells and adult stem cells. Embryonic stem cells can develop into all the cells of the adult body. Adult stem cells come from an organ or tissue and can develop into specialized types of cell within the organ or tissue. Hope this helps! Mark brainly please!
6 0
3 years ago
Combustion analysis of an unknown compound provides the following data: 73.5 grams C, 4.20 grams H, and 72.3 grams Cl. What is t
tino4ka555 [31]
The  %  composition  of  each  element  is  calculated  as   follows

=  mass   of  the  element/total  mass   x100

total  mass=  73.5+4.2+72.3=150
%  composition  of  C  =  73.5/150 x100=49%

%  composition  of  H= 4.2/150 x100=  2.8%

%composition  of  Cl=  72.3/150  x100=  48.2%
8 0
4 years ago
Determine the rate law and the value of k for the following reaction using the data provided.
blsea [12.9K]

<u>Answer:</u> The rate law expression is \text{Rate}=k[NO]^2[O_2]^1 and value of 'k' is 1.727\times 10^3M^{-2}s^{-1}

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

Rate law expression for the reaction:

\text{Rate}=k[NO]^a[O_2]^b

where,

a = order with respect to nitrogen monoxide

b = order with respect to oxygen

  • <u>Expression for rate law for first observation:</u>

8.55\times 10^{-3}=k(0.030)^a(0.0055)^b       ....(1)

  • <u>Expression for rate law for second observation:</u>

1.71\times 10^{-2}=k(0.030)^a(0.0110)^b       ....(2)

  • <u>Expression for rate law for third observation:</u>

3.42\times 10^{-2}=k(0.060)^a(0.0055)^b      ....(3)

Dividing 1 from 2, we get:

\frac{1.71\times 10^{-2}}{8.55\times 10^{-3}}=\frac{(0.030)^a(0.0110)^b}{(0.030)^a(0.0055)^b}\\\\2=2^b\\b=1

Dividing 1 from 3, we get:

\frac{3.42\times 10^{-2}}{8.55\times 10^{-3}}=\frac{(0.060)^a(0.0055)^b}{(0.030)^a(0.0055)^b}\\\\2^2=2^a\\a=2

Thus, the rate law becomes:

\text{Rate}=k[NO]^2[O_2]^1

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

8.55\times 10^{-3}=k[0.030]^2[0.0055]^1\\\\k=1.727\times 10^3M^{-2}s^{-1}

Hence, the rate law expression is \text{Rate}=k[NO]^2[O_2]^1 and value of 'k' is 1.727\times 10^3M^{-2}s^{-1}

4 0
3 years ago
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