Aldehydes and Ketones. Aldehydes and ketones are classes of organic compounds that contain a carbonyl (C=O) group.
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Answer:
2KCl + F₂ → 2KF + Cl₂
Explanation:
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
This law was given by French chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
2KCl + F₂ → 2KF + Cl₂
In this equation mass of reactant and product is equal. There are 2 potassium 2 chlorine and fluorine atoms on both side of equation it means mass remain conserved.
All other options are incorrect because mass is not conserved.
Mg₂ + LiBr ---> LiMg + Br
In this equation mass of magnesium is more on reactant side.
Na +O₂ ---> Na₂O
In this equation there is more oxygen and less sodium on reactant side while there is more sodium and less oxygen on product side.
H₂O ---> H₂ + O₂
In this equation there is less oxygen on reactant side while more oxygen on product side.
There are two main types of stem cell: embryonic stem cells and adult stem cells. Embryonic stem cells can develop into all the cells of the adult body. Adult stem cells come from an organ or tissue and can develop into specialized types of cell within the organ or tissue. Hope this helps! Mark brainly please!
The % composition of each element is calculated as follows
= mass of the element/total mass x100
total mass= 73.5+4.2+72.3=150
% composition of C = 73.5/150 x100=49%
% composition of H= 4.2/150 x100= 2.8%
%composition of Cl= 72.3/150 x100= 48.2%
<u>Answer:</u> The rate law expression is
and value of 'k' is 
<u>Explanation:</u>
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:

Rate law expression for the reaction:
![\text{Rate}=k[NO]^a[O_2]^b](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5Ea%5BO_2%5D%5Eb)
where,
a = order with respect to nitrogen monoxide
b = order with respect to oxygen
- <u>Expression for rate law for first observation:</u>
....(1)
- <u>Expression for rate law for second observation:</u>
....(2)
- <u>Expression for rate law for third observation:</u>
....(3)
Dividing 1 from 2, we get:

Dividing 1 from 3, we get:

Thus, the rate law becomes:
![\text{Rate}=k[NO]^2[O_2]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5E2%5BO_2%5D%5E1)
Now, calculating the value of 'k' by using any expression.
Putting values in equation 1, we get:
![8.55\times 10^{-3}=k[0.030]^2[0.0055]^1\\\\k=1.727\times 10^3M^{-2}s^{-1}](https://tex.z-dn.net/?f=8.55%5Ctimes%2010%5E%7B-3%7D%3Dk%5B0.030%5D%5E2%5B0.0055%5D%5E1%5C%5C%5C%5Ck%3D1.727%5Ctimes%2010%5E3M%5E%7B-2%7Ds%5E%7B-1%7D)
Hence, the rate law expression is
and value of 'k' is 