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Andreas93 [3]
3 years ago
9

What property has a higher value than silicon

Chemistry
1 answer:
Lana71 [14]3 years ago
4 0

I think is aluminium also

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Which of these solutes raises the boiling point of water the most?
Murljashka [212]

Answer:

D. ionic sodium phosphate (Na3PO4)

Explanation:

8 0
3 years ago
Please help thank you
Fynjy0 [20]

Answer:

D

Explanation:

8 0
3 years ago
Solid aluminum and gaseous oxygen react in a combination reaction to produce aluminum oxide: 4Al (s) + 3O2 (g) → 2Al2O3 (s) In
jek_recluse [69]

Answer: The percent yield of the reaction is 74 %

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

\text{Moles of aluminium}=\frac{2.5g}{27g/mol}=0.092mol

For oxygen gas:

\text{Moles of oxygen gas}=\frac{2.5g}{32g/mol}=0.078mol

The chemical equation for the reaction of titanium and chlorine gas follows:

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

By Stoichiometry of the reaction:

4 moles of aluminium reacts with 3 moles of oxygen.

So, 0.092 moles of aluminium reacts with = \frac{3}{4}\times 0.092=0.069mol of oxygen

As, given amount of oxygen is more than the required amount. So, it is considered as an excess reagent.

Thus, aluminium is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

4 moles of aluminium produce = 2 moles of Al_2O_3

So, 0.092 moles of aluminium will produce = \frac{2}{4}\times 0.092=0.046moles of Al_2O_3

Now, calculating the mass of aluminium oxide:

\text{Mass of aluminium oxide}=moles\times {\text {molar mas}}=0.046mol\times 102g/mol=4.7g

To calculate the percentage yield of titanium (IV) chloride, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield  = 3.5 g

Theoretical yield = 4.7 g

Putting values in above equation, we get:

\%\text{ yield of reaction}=\frac{3.5g}{4.7g}\times 100\\\\\% \text{yield of reaction}=74\%

Hence, the percent yield of the reaction is 74 %

6 0
3 years ago
How many moles of solute are in 300 mL of 1.5 M CaCl2? How many grams fo CaCl2 is this?
tester [92]

Answer:

1. 0.45 mole

2. 49.95g

Explanation:

The following were obtained from the question:

Volume of solution = 300mL = 300/1000 = 0.3L

Molarity = 1.5 M

Mole of CaCl2 =?

1. We can obtain the mole of the solute as follow:

Molarity = mole of solute /Volume of solution

1.5 = mole of solute/0.3

Mole of solute = 1.5 x 0.3

Mole of solute = 0.45 mole

2. The grams in 0.45 mole of CaCl2 can be obtained as follow:

Molar Mass of CaCl2 = 40 + (35.5 x 2) = 40 + 71 = 111g/mol

Mole of CaCl2 = 0.45 mole

Mass of CaCl2 =?

Mass = number of mole x molar Mass

Mass of CaCl2 = 0.45 x 111

Mass of CaCl2 = 49.95g

3 0
3 years ago
Read 2 more answers
Jane made this picture to represent a chemical reaction: Two circles, one white and the other gray are shown on the left. A smal
7nadin3 [17]

It represents a decomposition reaction because one reactant breaks apart and forms two products.

Explanation:

The type of chemical reaction depicted by Jane represents a decomposition reaction because on reactant breaks apart and forms two products.

In this reaction XY breaks apart to form X and Y. This is a decomposition reaction.

                     XY   →   X + Y

  • Decomposition or cracking is the formation of two or more products from a single reactant.
  • The break down of a compound into individual atoms or molecules falls into this category.
  • The extreme instability of a compound drives such a reaction.
  • The products is usually stable or it can dissociate further till it is stable.

      Find the image attached for more explanation:

Learn more:

Thermal decomposition brainly.com/question/11181911

#learnwithBrainly

8 0
4 years ago
Read 2 more answers
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