Given:
No of atoms present= 8.022 x 10^23 atoms
Now we know that 1 mole= 6.022 x 10^23 atoms
Hence number of moles present in 8.022 x 10^23 atoms is calculated as below.
Number of moles
= 8.022 x 10^23/6.022x 10^23
=1.3 moles.
Hence we have 1.3 moles present.
Answer:
The pKa of the conjugate acid is 17.7
Explanation:
If hydrogen is removed from water, the equilibrium concentration of the conjugate acid according to the information given in the question becomes,
Kₐ = [OH⁻]/[H₂O]
Now, we determine the equivalent pKa
pKa = -log[ka]
pKa = -log[100]
pKa = -2
Removal of hydrogen from water is reversible as shown below;
H₂O ⇄ OH⁻ + H⁺
15.7 -2
This reaction is reversible, and the difference in pKa = pKa[H₂O] - pKa[H⁺];
pKa of the conjugate acid = 15.7 - (-2) = 17.7
The pKa of the conjugate acid is 17.7
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Answer: 1000x
Explanation:
I hope this helped!
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- Zack Slocum
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Answer:
Fructose
Explanation:
A ketose is a monosaccharide containing one ketone group (RCOR) per molecule.
This means to identify a ketose, one has to look for the ketone group in the structural formuar of the compound.
Mannose - This is an aldose. It contains the aldehyde functional group.
Galactose - This is an aldose. It contains the aldehyde functional group.
Fructose - This is a keose. It contains the Ketone Functional group.
Glucose - This is an aldose. It contains the aldehyde functional group.