Answer:
9.8 L
Explanation:
The reaction that takes place is:
- 4H₂(g) + CS₂(g) → CH₄(g)+ 2H₂S(g)
At STP, 1 mol of any gas occupies 22.4 L.
We <u>calculate how many moles are there in 2.5 L of CH₄ at STP</u>:
- 2.5 L ÷ 22.4 L/mol = 0.11 mol CH₄
Then we <u>convert CH₄ moles into H₂ moles</u>, using the<em> stoichiometric coefficients of the reaction</em>:
- 0.11 mol CH₄ *
= 0.44 mol H₂
Finally we <u>calculate the volume that 0.44 moles of H₂ would occupy at STP</u>:
- 0.44 mol * 22.4 L/mol = 9.8 L