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3 years ago

I need help please!!!!!

Mathematics

2 answers:

elixir [45]3 years ago

7 0

Answer:

Step-by-step explanation:

88 ÷ (11 * 2) ÷ 4

88 ÷ 22 ÷ 4 = 11

AlekseyPX3 years ago

5 0

The answer is 11 because of pemdas

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65 - 2x ≥ 150, whats the answer!!!

Sidana [21]

Answer:

x <= -42.5

Step-by-step explanation:

65 - 2x >= 150

-2x >= 150 - 65

-2x >= 85

2x <= -85

x <= -85/2

x <= -42.5

6 0

2 years ago

Brianna is a waitress in an upscale restaurant. On Friday she waited on 12 groups of customers who spent an average of $186 per

givi [52]

Given :

Brianna is a waitress in an upscale restaurant. On Friday she waited on 12 groups of customers who spent an average of $186 per group.

Her tips averaged 18% of the total amount spent by all the groups of customers that day.

To Find :

Brianna's tip income earnings on Friday.

Solution :

Total amount of money spent by 12 groups :

P = $ 12×186 = $2232 .

She got tip of 18% of the total amount spent by all the groups of customers.

$T = P\times \dfrac{20}{100}\\\\T= 2232\times \dfrac{20}{100}\\\\T=\$446.4$

Brianna's tip income earnings on Friday is $446.4 .

Hence, this is the required solution.

4 0

3 years ago

Jay bought 6 bags of maize at shs 2700 each.He sold the bags at shs.3300 each. what was his profit?

NISA [10]

Answer:

3300-2700= 600 x 6 = 3600

7 0

2 years ago

Luna entered a raffle for a new pair of running shoes. She purchased 20 tickets and was told that she had a 20% chance of winnin

xenn [34]

Answer:

<h3>100 tickets</h3>

Step-by-step explanation:

Probability of winning = amount of tickets purchased/Total number of tickets

20% = 20/total number of tickets

20/100 = 20/total number of tickets

cross multiply

20 * total number of tickets = 20 * 100

20 * total number of tickets = 100

total number of tickets sold = 100 tickets

6 0

3 years ago

Read 2 more answers

Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx = 1$

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have

$\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx = 1$

Since c is a constant, we can bring it out of the integral sign; to give us

$c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx = 1$

Open the bracket

$c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx = 1$

Integrate with respect to y

$c\int\limits^3_0 {\frac{xy^{2}}{2} +\frac{xy^{3}}{3} } \, dx (0,3}) = 1$

Substitute 0 and 3 for y

$c\int\limits^3_0 {(\frac{x* 3^{2}}{2} +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2} +\frac{x * 0^{3}}{3})} \, dx = 1$

$c\int\limits^3_0 {(\frac{x* 9}{2} +\frac{x * 27}{3} ) - (0 +0) \, dx = 1$

$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

$\frac{c}{6}\int\limits^3_0 (81x ) \, dx = 1$

Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

$\frac{c}{6} * \frac{81 * 3^{2} - 81 * 0^{2}}{2} = 1$

$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

$\frac{729c}{12} = 1$

Multiply both sides by $\frac{12}{729}$

$c = \frac{12}{729}$

$c = 0.0165 (Approximately)$

8 0

3 years ago