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OverLord2011 [107]
4 years ago
14

I need help please!!!!!

Mathematics
2 answers:
elixir [45]4 years ago
7 0

Answer:

11

Step-by-step explanation:

88 ÷ (11 * 2) ÷ 4

88 ÷ 22 ÷ 4 = 11

AlekseyPX4 years ago
5 0
The answer is 11 because of pemdas
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I really dont understand this, im a A/B Honor role student just need a little help.
babymother [125]

Answer:

15 < 23

Could you include the numbers on D.? Thanks!

Step-by-step explanation:

They've been open for 15 hours, to reach 392 people. They can't be open for more than 23, because that would be more than 600 people. Therefore 23 need to be always GREATER than 15

15 < 23

see if you can find a number line that matches the expression.

Hope this helped! Please mark as brainliet! Thanks!

Me too! I'm an A/B Honor role student, but i get stuck and need help all the time. Not every one is perfect! ^_^

3 0
4 years ago
A number that is 5 more than twice x
iragen [17]
If x is any given number than I will use the Number five
Your equation will look like this
5^5=25
7 0
4 years ago
Please help me with number 14 name the propriety illustrated by the following
ASHA 777 [7]
A. .x -x=0
x+ -x=0
0=0
all real numbers are solutions
b. x-y+(-x)=x-y+(-x)
-y=-y
0=0
x=0/0 0 over 0
6 0
4 years ago
What is the value of a2 + 3b ÷ c − 2d, when a = 3, b = 8, c = 2, and d = 5?
Westkost [7]

Answer:

the answer is 8

Step-by-step explanation:

a2+3b÷c-2d

3×2+3×8÷2-10

6+24÷2-10

6+12-10

18-10

=8

8 0
2 years ago
Find S5 for the sequence 3, 13, 23, 33, 43, 53, 63, 73.
hoa [83]
 have an arithmetic sequence here....to find the common difference, subtract the first term from the second term. 13 - 3 = 10...so basically, ur adding 10 to each number to get to the next number.

before we find s5, we r going to find a5...because we need a5 to use in the sum formula.....a5 is the fifth term, and it is 43

sn = (n (a1 + a5) / 2
s5 = (5 (3 + 43) / 2
s5 = (5 (46)) / 2
s5 = 230/2
s5 = 115 <===

or, for this particular problem, s5 is the sum of the first 5 terms.
3 + 13 + 23 + 33 + 43 = 115.....u can do it this way for s5...but if u were asked to find s20, I suggest using the formula.
3 0
4 years ago
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