The quotient of a number and four increased by three.
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Answer:
B
Step-by-step explanation:
Of you put the values of c and y from B in the equation, then the result is,
![1 + 2 \times 1 \leqslant 4 \\ 1 + 2 \leqslant 4 \\ 3 \leqslant 4](https://tex.z-dn.net/?f=1%20%2B%202%20%5Ctimes%201%20%5Cleqslant%204%20%5C%5C%201%20%2B%202%20%5Cleqslant%204%20%5C%5C%203%20%5Cleqslant%204)
here, 3 is less than 4, which is true.
But the result will come out as greater than 4 if you put other points in the equation, which is not true for the given condition.
What we need to know is how much is 1/3 of 25 2/5.
We will be multiplying fraction by a fraction and for this, it's good to change mixed numbers into improper fractions:
25 2/5=
![\frac{23*5+2}{5}= \frac{117}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B23%2A5%2B2%7D%7B5%7D%3D%20%5Cfrac%7B117%7D%7B5%7D%20%20)
and now we multiply it by 1/3:
![\frac{1}{3}\frac{117}{5}=\frac{39}{5}=7\frac{4}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7B117%7D%7B5%7D%3D%5Cfrac%7B39%7D%7B5%7D%3D7%5Cfrac%7B4%7D%7B5%7D%20%20)
and that's the answer: the basketball equipment weights 7 4/5 pounds.
Answer:
Step-by-step explanation:
If you graph there would be two different regions. The first one would be
![y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%7Bx%7D%20%5C%2C%5C%2C%5C%2C%5C%2C%2C%200%5Cleq%20x%20%5Cleq%201%20%5C%5C)
And the second one would be
.
If you rotate the first region around the "y" axis you get that
![{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20A_1%20%3D%202%5Cpi%20%5Cint%5Climits_%7B0%7D%5E%7B1%7D%20x%5Csqrt%7Bx%7D%20dx%20%3D%20%5Cfrac%7B4%5Cpi%7D%7B5%7D%20%3D%202.51%20%7D)
And if you rotate the second region around the "y" axis you get that
![{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20A_2%20%3D%202%5Cpi%20%5Cint%5Climits_%7B1%7D%5E%7B2%7D%20x%282-x%29%20dx%20%3D%20%5Cfrac%7B4%5Cpi%7D%7B3%7D%20%3D%204.188%20%7D)
And the sum would be 2.51+4.188 = 6.698
If you revolve just the outer curve you get
If you rotate the first region around the x axis you get that
![{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20A_1%20%3D%5Cpi%20%5Cint%5Climits_%7B0%7D%5E%7B1%7D%20%28%20%5Csqrt%7Bx%7D%29%5E2%20dx%20%3D%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%3D%201.5708%20%7D)
And if you rotate the second region around the x axis you get that
![{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20A_2%20%3D%20%5Cpi%20%5Cint%5Climits_%7B1%7D%5E%7B2%7D%20%282-x%29%5E2%20dx%20%3D%20%5Cfrac%7B%5Cpi%7D%7B3%7D%20%3D%201.0472%20%7D)
And the sum would be 1.5708+1.0472 = 2.618