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anyanavicka [17]
4 years ago
6

Pls answer I will mark as brainliest-

Mathematics
1 answer:
Natali [406]4 years ago
3 0
On Oct 11: 1INR=0.04976AED
Oct 27 1INR=0.05022AED
However It's Price was highest on Oct 9 when 1AED was equal to 20.2395 INR
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What is= X less then 12
miskamm [114]

Answer:

12-x

Step-by-step explanation:

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3 years ago
What is 2 1/2 and 6 2/3 in simplest form
sergij07 [2.7K]
2 1/2=5/2 and 6 2/3= 20/3
8 0
4 years ago
What is a8 for the geometric sequence 6,561;−2,187;729;−243;…6,561;−2,187;729;−243;….
VMariaS [17]
Consider a geometric sequence (u_n)

let u_1=a and the common ratio be r, then the sequence is constructed as follows:

u_1, u_2, u_3..... = a, ar, a r^{2}, a r^{3}, ...

we can observe that each term of the sequence is its previous term * r.


In the given sequence, to find the common ratio we divide 6,561 by −2,187 and get -3. This means that r= -\frac{1}{3}

Let the first term u_1=a=6,561, 

then the eighth term is  

u_8=a* r^{7}= 6,561 (- \frac{1}{3} )^{7}= -6,561*( \frac{1}{3} )^{7}= \frac{-6,561}{2187} =-3


Answer: -3
4 0
4 years ago
A company prepares their shipments in two different-sized boxes.
fgiga [73]

Answer:

Answer is A.  -296x+960/ -636x+3,024

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee
blagie [28]

Question

Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?

a)39x+30<45x+18

b) 45x+18>39x+30

c) 45x+18<39x+30

d)39x+18<45x+30

Answer:

c) 45x+18<39x+30

Step-by-step explanation:

Step 1

We have to find the Algebraic expressions for the cable companies

Cable company A charges $45 a month for cable plus a $18 installation fee.

Let the number of months be represented as x

Hence, this is represented as:

$45 × x + $18

= 45x + 18

Cable B charges $39 a month for cable plus a $30 fee for installation.

Let the number of months be represented as x

Hence, this is represented as:

$39 × x + $30

= 39x + 30

The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?

= Cable company A < Cable company B

= 45x + 18 < 39x + 30

Therefore option c is correct

8 0
3 years ago
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