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Fed [463]
3 years ago
13

Show your work with good use of units, rounding, and significant figures. [Hint: it is good practice to show the value of your a

nswer before you round off to the final answer with the correct significant figures!]
(8 points) Ammonia, NH3(g)and hydrogen chloride, HCl(g) react to form solid ammonium chloride NH4Cl(s).

NH3(g) + HCl(g) LaTeX: \longrightarrow⟶ NH4Cl(s)

Two 5.00 L flasks at 35.0.°C are connected by a stopcock. One flask contains 7.00 g of NH3(g) and the other contains 16.00 g of HCl(g) When the stopcock is open, the gases react until one is completely consumed. Which gas remains in the system after the reaction is complete? What will be the final pressure of the system after the reaction is complete? (Neglect the volume of the ammonium chloride formed).
Chemistry
1 answer:
Neporo4naja [7]3 years ago
7 0

:?Answer:

:?Answer:

Explanation:

:?Answer:

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How much water (H2O ) would form if 4.04 g of hydrogen (H2) reacted with 31.98 g of oxygen (O2 )?
Norma-Jean [14]

Answer:

Mass = 36 g

Explanation:

Given data:

Mass of water formed = ?

Mass of hydrogen = 4.04 g

Mass of oxygen = 31.98 g

Solution:

Chemical equation:

2H₂ + O₂   →   2H₂O

Number of moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 4.04 g/ 2 g/mol

Number of moles = 2.02 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 31.98 g/ 32 g/mol

Number of moles = 1.0 mol

Now we will compare the moles of water with hydrogen and oxygen.

                O₂         :         H₂O

                 1           :           2

                H₂         :         H₂O

                 2          :          2

               2.02       :      2.02

Number of moles of water formed by oxygen are less thus oxygen will limiting reactant.

Mass of water:

Mass = number of moles × molar mass

Mass = 2 mol × 18 g/mol

Mass = 36 g

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