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Llana [10]
3 years ago
11

A compound containing phosphorus and oxygen has a molar mass of 219.9 g/mol and an empirical formula of p2o3. Determine its mole

cular formula.
Chemistry
1 answer:
Softa [21]3 years ago
7 0

Answer:

P₄O₆

Explanation:

The molecular formula is a whole number multiple of the empirical formula. that is, if the mole wt is 219.9 gms/mole and the empirical formula weight is 110 gms/mole*, then the whole number multiple is 219.9/110 = 2 => Molecular formula => (P₂O₄)₂ => P₄O₆.

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the mass number of a chromium Atom is 52 and it has 24 protons. How many neutrons does this atom have?
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Chromium has a total of 28 neutrons. This is found because we subtract the number of protons (the atomic number) from the mass number. 52 minus 24 gives us 28. It also has 24 electrons.

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Boiling water is frequently used to kill parasites within the water. If you are boiling fresh water, and liquid water remains in
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Answer: hello dear, your question seems incomplete, but, chill out not to worry let me give you one or two things you need to know in order to be able to solve this kind of question in the nearest future, check this out!.

Explanation:

In order to kill parasites and to make the water the be safe from microoganisms, boiling is a great procedure for making sure this happens, that is to say is the act of purification of water. However, when you over-boil water it also depletes the amount of oxygen present in the water.

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7 0
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Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron. 3Mg(s) +
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Answer:

Theanswer to your question is:

Limiting reactant = FeCl₃

Excess reactant = 1.66 g of Mg

Explanation:

Data

Mg = 41 g   = 24.31 g/mol

FeCl₃ = 175 g = 162.2 g/mol

                         3Mg(s) + 2FeCl₃(s) → 3MgCl₂(s) + 2Fe(s)

                      3(24.31) of Mg ------------------  2(162.2)  of FeCl₃

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Theoretical Proportion = 324.4/72.93 = 4.44

Practical proportion   =  175 / 41 = 4.2

As the proportion disminishes the limiting reactant is FeCl₃.

Excess reactant

                               72.93 g of Mg ------------------ 324.4 g of FeCl₃

                                   x -------------------------           175 g of FeCl₃

x = (175 x 72.93) / 324.4

x = 39.34 g of Mg

Excess = 41 - 39.34

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