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Llana [10]
3 years ago
11

A compound containing phosphorus and oxygen has a molar mass of 219.9 g/mol and an empirical formula of p2o3. Determine its mole

cular formula.
Chemistry
1 answer:
Softa [21]3 years ago
7 0

Answer:

P₄O₆

Explanation:

The molecular formula is a whole number multiple of the empirical formula. that is, if the mole wt is 219.9 gms/mole and the empirical formula weight is 110 gms/mole*, then the whole number multiple is 219.9/110 = 2 => Molecular formula => (P₂O₄)₂ => P₄O₆.

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Pyridine, C5H5N, is a polar organic solvent. How many carbon atoms are in 7.05 moles of pyridine? 4.24 x 1024 4.24 x 10, 24 2.12
leonid [27]

Answer:

2.122×10^25atoms

Explanation:

number of moles=mass/molar mass

7.05moles= mass of pyridine/79

reacting mass of pyridine=556.95

C5H5N= (12×5)+(5)+(14)=79

C5=60

to find the mass of carbon in 556.95g of pyridine we take the stoichometric ratio

60[C5] -----> 79[C5H5N]

x[C5] --------> 556.95g[C5H5N]

cross multiply

x=(60×556.95)/79

x=423g of carbon

moles=mass/molar mass

moles of carbon=423/12

moles=35.25moles of carbon

moles=number of particles/Avogadro's constant

35.25=number of particles/6.02×10^23

number of particles=2.122×10^25atoms of carbon

3 0
3 years ago
How do you become good at math
Veronika [31]
• Ask questions when you need help.

• Take notes.

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6 0
3 years ago
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The highest pressure ever produced in a laboratory setting was about 2.0 x 10 6 atm. If we have a
tigry1 [53]

Answer:

Volume = 72.7272

Explanation:

if only pressure and volume change, then we can do some simple math to find the answer.

2 x 10 ^ 6 times 1 x 10 ^-5 = 20

pressure and volume must equal 20

20 = 0.275 x volume

20 / 0.275 = new volume

I don't remember significant digits but your volume is 72.72727272 just repeated

8 0
3 years ago
If the relative rate of diffusion of ozone as compared to chlorine is 6:3 and further if the density of chlorine is 36 Find out
Alexandra [31]

Answer:

The density of ozone is 4.24.

Explanation:

The relation between the relative rate of diffusion and density is given by :

r\propto \dfrac{1}{\sqrt d}

The given ratio of the relative rate of diffusion of ozone as compared to chlorine is 6:3.

Let the density of ozone is d₂.

\dfrac{r_1}{r_2}=\sqrt{\dfrac{d_2}{d_1}} \\\\\dfrac{6}{3}=\sqrt{\dfrac{d_2}{36}} \\\\3=\dfrac{\sqrt{d_2}}{6}\\\\d_2=\sqrt{18} \\\\d_2=4.24

So, the density of ozone is 4.24.

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3 years ago
Difference between NaOH and HCI ​
morpeh [17]
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