What acid and what base would react in aqueous solution so that the following salts appear as products in the molecular equation
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Answer: -
Volume of NaOH = 461 mL = 461/1000 = 0.461 L
pH = 10.0
Using the relation pH + pOH = 14.00
pOH = 14.00 - 10.00= 4.00
Using the relation
[OH⁻] =
= M
Since NaOH is a monobasic acid,
[NaOH] = [OH⁻] = M
Amount of NaOH = [NaOH] x Volume of NaOH
= M x 0.461 L
= 4.61 x 10⁻⁵ mol
Molar mass of NaOH = 23 x 1 + 16 x 1 + 1 x1
= 40 g / mol
Mass of NaOH required = 4.61 x 10⁻⁵ mol x 40 g/ mol
= 1.84 x 10⁻³ g