How much naoh is needed to prepare 461 ml of solution with a ph of 10.00?
1 answer:
Answer: -
Volume of NaOH = 461 mL = 461/1000 = 0.461 L
pH = 10.0
Using the relation pH + pOH = 14.00
pOH = 14.00 - 10.00= 4.00
Using the relation
[OH⁻] =
= M
Since NaOH is a monobasic acid,
[NaOH] = [OH⁻] = M
Amount of NaOH = [NaOH] x Volume of NaOH
= M x 0.461 L
= 4.61 x 10⁻⁵ mol
Molar mass of NaOH = 23 x 1 + 16 x 1 + 1 x1
= 40 g / mol
Mass of NaOH required = 4.61 x 10⁻⁵ mol x 40 g/ mol
= 1.84 x 10⁻³ g
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Answer:
The correct answer is - option C.
Explanation:
Given: the melting point of HCl is
-114.8 °C, which suggests that below this temperature HCl will be solid.
and, since the boiling point of HCl is - 85.1 °C. It is also suggested that above this temperature HCl will be gas, Therefore.
Solid -114.8 - Ordered arrangement
Liquid -85.1c - Less orderly arranged
Gaseous - Least orderly arranged
Thus, at —90 °C, HCl will be present 'in the liquid state, At — 1 °C, HCl will be present in the gaseous state and at -129 °C, HCl will be present in the solid-state. So, the molecules will be organized in a more orderly manner .
Thus, the correct answer is - option C
