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3 years ago

If a projectile flies 387 meters north in 8.5 seconds, what is its velocity?

1 answer:

4 0

Ok so velocity is speed but includes direction. The formula for both speed velocity is distance over time. so the equation is 387 over 8.5. That equals 45.5294117647 which can be rounded to 46.

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Which term labels solution?

Natalija [7]

What are the answer? For me to help you I need to see them

3 0

4 years ago

A chemist weighs out 0.0865 g of sulfurous acid, H2SO3, which is a diprotic acid into a 250. mL of volumetric flask and dilutes

kobusy [5.1K]

Answer: The volume of NaOH needed to add is 12.35 mL

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of sulfurous acid = 0.0865 g

Molar mass of sulfurous acid = 82.079 g/mol

Volume of solution = 250 mL

Putting values in above equation, we get:

$\text{Molarity of sulfurous acid}=\frac{0.0865\times 1000}{82.079\times 250}\\\\\text{Molarity of sulfurous acid}=0.0042M$

To calculate the volume of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_3$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=0.0042M\\V_1=250mL\\n_2=1\\M_2=0.1700M\\V_2=?mL$

Putting values in above equation, we get:

$2\times 0.0042\times 250=1\times 0.1700\times V_2\\\\V_2=\frac{2\times 0.0042\times 250}{1\times 0.1700}=12.35mL$

Hence, the volume of NaOH needed to add is 12.35 mL

3 0

4 years ago

The only way to break the bonds in a compound is with a

Sveta_85 [38]

Answer:

I think chemical reaction

Explanation:

8 0

3 years ago

Read 2 more answers

A substance joined by this type of bond has a low melting point

cestrela7 [59]

Covalent compounds have bonds where electrons are shared between atoms. Due to the sharing of electrons, they exhibit characteristic physical properties that include lower melting points and electrical conductivity compared to ionic compounds.

5 0

3 years ago

Read 2 more answers

69 whenever organic matter is decomposed under oxygen-free(anaerobic) conditions, methane is one of the products. thus,enormous

Lina20 [59]

The solution is as follows:

The problem would only need the information of 5,600 EJ for the known sources of methane. The molar mass of methane is 16 g/mol.

802 kJ/mol(1000 J/ 1 kJ)(1 mol/16 g)(1000 g/1 kg)(x kg) = 5,600 EJ(10¹⁸ J/1 EJ)
Solving for x,
x = 1.18×10¹⁴ kg of natural gas or methane

8 0

4 years ago