Molar heat capacity is greater than heat capacity. the molar heat capacity of a substance is the particular heat c instances the molar mass of the substance M/N its numerical price is generally smaller than that of the particular warmness. Paraffin wax, for example, has a specific heat of about 2500 J⋅K−1⋅kg−1 but a molar heat capacity of about 600 J⋅K−1⋅mol−1.
Heat capacity or precise warmth is the quantity of warmth in keeping with unit mass that is required to elevate the temperature by 1°C. specific heat is helpful in figuring out the processing temperatures and amount of warmth necessary for processing and may be useful in differentiating among polymeric composites.
The warmth ability of an object describes how a good deal of heat energy is needed to boom the temperature of the object by way of 1 Kelvin (1 °C). word: bodily portions which might be related to the mass are called “specific” quantities and are regularly denoted by way of a decrease case letter.
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Answer:
both will be at liquid state. the particles will move rapidly in all directions and will collide with other particles in random motion
Substances that dissolve in water to yield ions are called electrolytes.
<u>Answer: </u>One isotope has a percentage abundance of 75.75 % and the percentage abundance of another isotope is 24.24%.
<u>Explanation:</u>
We are given the two stable isotopes of chlorine with their respective masses. The average atomic mass of chlorine is also given.
Average atomic mass of chlorine = 35.45 amu.
Let us assume the fractional abundance of one isotope be 'x' and the fractional abundance for another isotope will be (1 - x) because the total fractional abundance is always equal to 1.
Fractional abundance = x
Mass = 34.97 amu
Fractional abundance = 1 - x
Mass = 36.95 amu
The formula for the calculation of average atomic mass is given by:
Putting values in above equation, we get:
Converting these two fractional abundances into percentage abundances by multiplying it with 100.
Hence, one isotope has a percentage abundance of 75.75 % and the percentage abundance of another isotope is 24.24%.
Answer:
5.06atm
Explanation:
Using the combined gas law equation;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (Litres)
V2 = final volume (Litres)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question;
P1 = 1.34 atm
P2 = ?
V1 = 5.48 L
V2 = 1.32 L
T1 = 61 °C = 61 + 273 = 334K
T2 = 31 °C = 31 + 273 = 304K
Using P1V1/T1 = P2V2/T2
1.34 × 5.48/334 = P2 × 1.32/304
7.34/334 = 1.32P2/304
Cross multiply
334 × 1.32P2 = 304 × 7.34
440.88P2 = 2231.36
P2 = 2231.36/440.88
P2 = 5.06
The final pressure is 5.06atm