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vfiekz [6]
3 years ago
10

Red light has a wavelength of about 6.5 x 10-7m. Find its frequency. Show all work.

Chemistry
1 answer:
ozzi3 years ago
3 0
For this problem we use the wave equation. It is expressed as the speed (c) is equal to the product of frequency (f) and wavelength (v).

c = v x f

We know the wavelength of the an red light which is 6.5 x 10^-7 m. Now, we solve for the wavelength of the unknown wave to see the relation between the two waves.

2.998 X 10^8 = 5.3 X 10^15 X v
v = 2.998 X 10^8 / (5.3 X 10^15) = 5.657 X 10^-8 m

Therefore, the wavelength of the unknown wave is less than the wavelength of the red light.
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80.0 mL of 0.30 M NaOH and 80.0 mL of 0.30 M HCl are mixed together. What is the approximate pH
Licemer1 [7]

Answer:

  • <u><em>Neutral</em></u>

Explanation:

The number of moles of solute is equal to product of the molar concentration (molarity) and the volume (in liters) of solution.

Since the volumes and the molar concentrations of the<em> NaOH </em>and <em>HCl </em>solutions mixed are equal, each one of them contributes the same number of moles of solute.

Since every mol of NaOH produces one mol of OH⁻ ions and every mol of HCl produces one mol of H⁺ ion, the number of moles of OH ⁻ and H⁺ in solution are equal.

Thus, OH⁻ and H⁺ ions will be neutralized by the reaction:

  • OH⁻ (aq) + H⁺ (aq) ⇄ H₂O (l)

Which is strongly shifted to the right and has <em>neutral pH</em>.

Hence, you conclude that the approximate <em>pH of the solution is neutral.</em>

6 0
4 years ago
27.2g CuCl2 was dissolved in 2.50 L of the water. What is the molality of the solution?
stealth61 [152]

5.167g of calcium chloride is dissolved in 101.0mL of water in a calorimeter whose calorimeter constant is 15.3J/°C. The temperature rises from 18.4°C to 27.2 ...

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3 years ago
What is the mass of a sample of iron if that sample lost 2300J of heat energy when it cooled from 80 oC to 30°C? The specific he
irakobra [83]
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Equation:
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We have: quantity of heat : 2300J
specific heat: .449 J/g
difference in t: 80 - 30 = 50
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2 sig-figs --> 102 grams
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because the gas particles are forced closer together.
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Oksi-84 [34.3K]

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