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sashaice [31]
3 years ago
8

Chemical senses require _____ for transduction to occurgustatory and olfactory are the chemical senses required for transduction

to occur.
Chemistry
2 answers:
Evgen [1.6K]3 years ago
4 0
Chemical senses require moisture, or water, for transduction to occur.
Alexxx [7]3 years ago
3 0

Answer : Stimulus.

Explanation : Chemical senses require stimulus for transduction to occur.

Gustatory and olfactory are the chemical senses required for transduction to occur.

There are chemo-receptors present in the olfactory and gustatory, which responds to chemicals in aqueous solution through chemical senses.

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14. What is the pH of a 0.24 M solution of sodium propionate, NaC3H502, at 25°C? (For
Murrr4er [49]

Answer:

9.1

Explanation:

Step 1: Calculate the basic dissociation constant of propionate ion (Kb)

Sodium propionate is a strong electrolyte that dissociates according to the following equation.

NaC₃H₅O₂ ⇒ Na⁺ + C₃H₅O₂⁻

Propionate is the conjugate base of propionic acid according to the following equation.

C₃H₅O₂⁻ + H₂O ⇄ HC₃H₅O₂ + OH⁻

We can calculate Kb for propionate using the following expression.

Ka × Kb = Kw

Kb = Kw/Ka = 1.0 × 10⁻¹⁴/1.3 × 10⁻⁵ = 7.7 × 10⁻¹⁰

Step 2: Calculate the concentration of OH⁻

The concentration of the base (Cb) is 0.24 M. We can calculate [OH⁻] using the following expression.

[OH⁻] = √(Kb × Cb) = √(7.7 × 10⁻¹⁰ × 0.24) = 1.4 × 10⁻⁵ M

Step 3: Calculate the concentration of H⁺

We will use the following expression.

Kw = [H⁺] × [OH⁻]

[H⁺] = Kw/[OH⁻] = 1.0 × 10⁻¹⁴/1.4 × 10⁻⁵ = 7.1 × 10⁻¹⁰ M

Step 4: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺] = -log 7.1 × 10⁻¹⁰ = 9.1

5 0
3 years ago
How does a balanced chemical equation demonstrate conservation of mass?
Mariulka [41]

Answer:

A balanced chemical equation will demonstrate the law of conservation of mass because the amount of elements on one side (reactants) will equal the amount of elements on the other side (products).

Explanation:

CH₄ + 4Cl₂ -> CCl₄ + 4HCl

Reactants:

1 C

4 H

8 Cl

Products:

1 C

4 H

8 Cl

6 0
2 years ago
Read 2 more answers
The cylinder of aluminum in class was approximately 13mm in circumference and 42mm in length. What would be it's approximate mas
Roman55 [17]

Answer:

Mass, m = 1.51 grams

Explanation:

It is given that,

The circumference of Aluminium cylinder, C = 13 mm = 1.3 cm

Length of the cylinder, h = 4.2 cm

We know that the density of the Aluminium is 2.7 g/cm³

Circumference, C = 2πr

r=\dfrac{C}{2\pi}\\\\r=\dfrac{1.3}{2\pi}\\\\r=0.206\ cm

Density is equal to mass per unit volume.

d=\dfrac{m}{V}

m is mass of the cylinder

V is the volume of the cylinder

V=\pi r^2h\\\\V=\dfrac{22}{7}\times0.206^2\times 4.2\\\\V=0.5601\ cm^3

So,

m=d\times V\\\\m=2.7\times 0.5601\\\\m=1.51\ g

So, the mass of the cylinder is 1.51 grams.

5 0
3 years ago
I need help on this plsss
Firlakuza [10]

Answer:

An engine that creates ignites fuel with highly compressed air.

6 0
2 years ago
Read 2 more answers
When naming a binary compound, what ending do you use to represent anions?
spin [16.1K]
I believe You replace the ending of the elements name with -ide. example: magnesium flourine should should be magnesium flouride. 
6 0
2 years ago
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