when an atom is decaying, what number of half lives or percent does it need to decay to to become it's daughter element?

What`s the lewis structure for CH3OO?

DIA [1.3K]

I found this off youtube, I hope it helps.

6 0

3 years ago

I just randomly remembered my 9 year old sister telling my 14 year old crush that he looks like and elf... she goes "You're like

iVinArrow [24]

Answer:

thats pretty epic

Explanation:

6 0

3 years ago

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Suppose that you place exactly 100 bacteria into a flask containing nutrients for the bacteria and that you find the following d

tresset_1 [31]

Answer:

The order of the production of bacteria is 1.

12,787 bacteria will be present after 112 min.

$0.04331 min^{-1}$ is the rate constant for the process.

Explanation:

Rate of formation of bacteria when there 100 bacteria: R

Rate of formation of bacteria when there 200 bacteria: R' =2R

Rate of formation of bacteria is directly proportional to the number of bacteria:

$\frac{R}{R'}=\frac{k[200]^x}{k[400]^x}$

$\frac{R}{2R}=(\frac{200}{400})^x$

x = 1

The order of the production of bacteria is 1.

The half life of the process = $t_{1/2}=16 minutes$

Rate constant of the process = k

For first order process k is only dependent on half life:

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{16 min}=0.04331 min^{-1}$

For the first order process the increment numbers is given ;

$N=N_o\times e^{kt}$

Where:

$N_o$ = Initial population

N = Population after time t.

We have ;

$N_o=100$

t = 112 minutes

$N=100\times e^{0.04331 min^{-1}\times 112 min}$

$N = 12,786.82\approx 12,787$

12,787 bacteria will be present after 112 min.

$0.04331 min^{-1}$ is the rate constant for the process.

5 0

3 years ago

Copper has two isotopes. The one isotope (Copper-63) has an abundance of 69.2% and a mass of 62.930 amu. The second isotope (Cop

Step2247 [10]

Multiply the percentage by the mass for both and add them to get 63.545 amu

8 0

3 years ago

As a science major, you are assigned to the "Atomic Dorm" at college. The first floor has one suite with one bedroom that has a

lidiya [134]

Explanation:

A.

The first student will be on the lower bunk on the first floor because 1. They want on the lowest available floor and 2. They want to be in a lower bunk if available.

B.

7 students are in the TOP bunks because 1. They want on the lowest available floor and 2. They want to be in a lower bunk if available. Therefore, all the rooms up till the third floor (Remember, third floor has 3 suites), so the first floor is filled - 1 person on the top bunk, 2 floor is filled- 4 persons and the third floor; the first suite is filled - 1 person and the second suite is a little partially filled- 1 person.

C.

Following the criteria 1, 2 and 3, the 21st student occupies the third suite on the third floor because all the floors (1 and 2) are occupied so the third suite on the third floor is still vacant.

D.

From the criteria there are therefore 10 persons at the TOP bunk. All the rooms up till the third floor are filled, so the first floor is filled - 1 person on the top bunk, second floor is filled (2 suites) - 4 persons and the third floor; the first suite and second suite is filled - 4 persons; the thirs suite has 6 persons present so 1 person is at the top bunk.

8 0

3 years ago