Answer:
CaCN₂
Explanation:
A compound of calcium, carbon and nitrogen CaₐCₓNₙ in oxygen will burning producing:
CaₐCₓNₙ + O₂ → aCaO + xCO₂ + nNO₂
Moles of the oxides CaO, CO₂, NO₂ are:
CaO: 3.106g ₓ (1 mole / 56.08g) = <em>0.0554 moles of CaO = moles of Ca</em>
CO₂: 2.439g ₓ (1mole / 44g) = <em>0.0554 moles CO₂ = moles C</em>
NO₂: 5.097g ₓ (1mole / 46g) = <em>0.111 moles NO₂ = moles N</em>
Empirical formula is the chemical formula that represents the simplest ratio of elements in a compound.
Having as basis 0.0554 moles (The lower number of moles):
0.0554 moles Ca / 0.0554 = 1 Ca
0.0554 moles C / 0.0554 = 1 C
0.111 moles N / 0.0554 = 2N
Thus, the compound CaₐCₓNₙ has as empirical formula:
Ca₁C₁N₂ = <em>CaCN₂</em>
Answer:
Option B: ΔH is (+); endothermic
Explanation:
From the reaction Cl2 → 2Cl(g) given, we can see that the number of moles on the left hand side is 1 while on right hand side, it is 2. This means the number of moles are increasing and it means that the randomness of the system has increased. Also, the bonds are being broken down.
Therefore, the reaction is endothermic. In endothermic reactions, ΔH is positive.
Thus, the correct option is option B.
Answer:
If the chef is in a hurry we would assume he would want the pan to heat up so copper
Explanation:
Answer:
12.044 ×10²³ molecules of HCl
Explanation:
Given data:
Number of moles of MgO = 1 mol
Number of molecules of HCl react = ?
Solution:
Chemical equation:
MgO + 2HCl → MgCl₂ + H₂O
with 1 mole of MgO 2 moles of HCl are react.
Number of molecules of HCl react:
1 mole contain 6.022×10²³ molecules
2 mol × 6.022×10²³ molecules / 1 mol
12.044 ×10²³ molecules
The answer for the following problem is mentioned below.
Therefore the Gibbs free energy (ΔG) for the reaction is <u><em>-394.36 J</em></u>
Explanation:
Given:
ΔH = -393.5 kJ/ mol
ΔS =0.0029 kJ/mol K
T = 298 K
To solve:
Gibbs free energy (ΔG)
We know;
<u>ΔG = ΔH - TΔS </u>
ΔG = -393.5 - (298 × 0.0029)
ΔG = -393.5 - 0.8642
<u><em>ΔG = -394.36 J</em></u>
Therefore the Gibbs free energy (ΔG) for the reaction is <u><em>-394.36 J</em></u>
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