My educated guess should be the 3rd one
Answer:
i can't see the image so sorry
Explanation:
i couldnt see the imagee
Cm^3 = mL
1.11 g/cm^3 = 1.11 g/mL
Density (g/mL) multiplied by volume (mL) will give us the mass (g)
1.11 g/mL * 387 mL = 429.57 g
And since we have 3 significant figures, we have 430. g.
Answer:
O2
Explanation:
for find the limiting reactant you must calculate the moles of the reactants from the amount that you have and from the MM:
MM FeS2 = 120n = 26.2g / 120g/mol = 0,218 mol
MM O2 = 32n = 5,44g/32g/mol = 0,17 mol
The limiting reactant is
O2
Answer:
The answer to your question is: V2 = 1.94 l
Explanation:
Data
V1 = 2.42 l
T1 = 25°C
P1 = 1 atm
V2 = ?
T2 = 25 -11 = 14°C
P2 = 1(0.7) = 0.7 atm
Formula
P1V1/T1 = P2V2/T2
Clear V2 from the equation
V2 = P1V1T2/ P2T1
V2 = (1)((2.42)(14) / (0.7)(25)
V2 = 33.88 / 17.5
V2 = 1.94 l
