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3 years ago

Roasting battle, Bored xD

Chemistry

2 answers:

Kaylis [27]3 years ago

7 0

Answer:

hmmmmm

Explanation:

seems kinda sus

Assoli18 [71]3 years ago

6 0

Answer: ok lets battle XD

Explanation:

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The substance being dissolved is known as the __________.

pishuonlain [190]

a. solute. The solute is the substance usually dissolved in the solvent to form the solution.

5 0

3 years ago

Read 2 more answers

a plant fertilizer contains 15% by mass nitrogen. in a container of soluble plant food. there are 10.0 oz of fertilizer . how ma

trasher [3.6K]

If we convert the ounces to grams, there are approximately 283.495 grams of plant fertiliser

If nitrogen has 15% of this, all we have to do is divide this number by 100 to get the mass of 1% and multiply it by 15.

In the end, we end up with the mass of 42.5243 g

Hope I helped! xx

7 0

3 years ago

Balancing chemical equations! need help!!! don’t mind how i wrote it.

elena-s [515]

Answer:

2 KCIO₃ → 2 KCI + 3 O₂

Explanation:

A chemical equation is balanced when the number of atoms of each element is equal on both sides of the equation.

You have already identified the initial number of atoms of each element on both sides of the equation. As a rule of thumb, we balance the number of oxygen and hydrogen atoms last.

However, since all the other elements are already balanced, we shall start by balancing the number of oxygen atoms.

The lowest common multiple of 2 and 3 is 6. Thus, we shall ensure that both sides of the equation has 6 oxygen atoms.

2 KCIO₃ → KCI + 3 O₂

Reactants

K --- 2

C--- 2

I --- 2

O --- 6

Products

K --- 1

C --- 1

I --- 1

O --- 6

Notice that number of K, C and I atoms on the left-hand side of the equation has also changed.

2 KCIO₃ → 2 KCI + 3 O₂

Reactants

K --- 2

C --- 2

I --- 2

O --- 6

Products

K --- 2

C --- 2

I --- 2

O --- 6

The equation is now balanced.

4 0

3 years ago

What is the empirical formula for propene (C3H6)? C2H4 O C4H8 O C3H6 O CH2

Scilla [17]

Answer: C2H4 C4H8 C3H6.

Explanation:

3 0

3 years ago

Read 2 more answers

A solution is made by dissolving 4.35 g of glucose (C6H1206) in 25.0 mL of water at 25 °C.Calculate the molality of glucose in t

Roman55 [17]

Answer:

The molality is unchanged (0.96 molal)

Explanation:

Step 1: Data given

mass of glucose = 4.35 grams

volume of water = 25.0 mL

Density of water = 1.00 g/mL

Molar mass of glucose = 180.156 g/mol

Step 2: Calculate number of moles

moles of glucose = mass of glucose / Molar mass of glucose

moles of glucose = 4.35 grams / 180.156 g/mol

moles of glucose = 0.024 moles

Step 3: Calculate mass of water

mass = density * volume

mass of water = 1.00 g/mL * 25.0 mL

mass of water = 25 g = 0.025 kg

Step 4: Calculate molality

molality = Number of moles / mass of water

molality = 0.024 moles / 0.025 kg

molality = 0.96 molal

Suppose you take a solution and add more solvent, so that the original mass of solvent is doubled.

This means double mass of water = 2*0.025 kg = 0.050 kg

Now molality is 0.024 moles / 0.050 kg = 0.48 molal

When the mass of solvent is doubled, the molality is halved from 0.96 molal to 0.48 molal

You take this newsolution and add more solute, so that the original mass of the solute is doubled.

This means double mass of glucose = 2*4.35 g = 8.70 g

8.70 grams of glucose = 8.7 grams * 180.156 g/mol = 0.048 moles

molality = 0.048 moles / 0.050 kg = 0.96 molal

The molality is unchanged

5 0

4 years ago