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2 years ago

2 Na2O + CO = Na2CO3 + Na

Chemistry

1 answer:

Vikki [24]2 years ago

8 0

Moles of Na_2O

Given mass/Molar mass
35/62
0.56mol

2 mols Na_2O produces 1 mol sodium carbonate.

1 mol sodium oxide produces 0.5mol sodium carbonate

Moles of sodium carbonate

0.56(0.5)
0.28mol

Molar mass

2(23)+12+3(16)
46+12+48
106g/mol

Mass

0.28(106)
29.7g

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List the four different sublevels and (given that only a maximum of two electrons can occupy an orbital) determine the maximum n

timurjin [86]

Answer:

l = 0 → s = 2 electrons;

l = 1 → p = 6 electrons;

l = 2 → d = 10 electrons;

l= 3 → f = 14 electrons.

Explanation:

For the quantum theory, the probability to find an electron is higher in the space region called orbital. It's impossible to determine where the electron is and his velocity at the same time (uncertainty principle). So, the theory determines four quantum numbers to characterize an electron, so it's easy to identify it:

n is the principal quantum number and identify the shell where the electron is. It varies from 1 to 7 and is represented by the letters K, L, M, N, O, P, and Q;

l is the azimuthal quantum number and identify the subshell (or sublevel) where the electron is. It varies from 0 to 3 and is represented by the letters s, p, d, and f;

ml is the magnetic quantum number, and it represents the orbital. It varies from -l to +l, passing by 0. Each orbital can have at least 2 electrons;

ms is the spin number and represents the spin of the electrons. It can be +1/2 or - 1/2.

Then, the sublevel s (l= 0) only has 1 orbital (ml = 0) so, it can have ate least 2 electrons; the sublevel p (l= 1) has 3 orbitals (ml = -1, ml= 0, ml = +1), so it can have at least 6 electrons; the sublevel d (l = 2) has 5 orbitals (ml = -2, ml = -1, ml = 0, ml = +1, ml = +2), so it can have at least 10 electrons; and the sublevel f (l = 3) has 7 orbitals (ml = -3, ml = -2, ml = -1, ml = 0, ml = +1, ml = +2, ml = +3), so it can have at least 14 electrons.

8 0

4 years ago

plants are able to carry out photosynthesis because they contain the organelle known as an mitochondrion . is that true or false

MakcuM [25]

That's false. Animals have mitochondria too. It's responsible for cellular respiration, not photosynthesis.

3 0

4 years ago

Hypernatremia due to excess water loss: A. Diabetes insipidus B. Dialysis fluid excess C. Hyperaldosteronism D. Older persons

alex41 [277]

Answer:

Hypernantremia due to excess water loss

A. Diabetes insipidus

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-Levi

5 0

2 years ago

Read 2 more answers

The reaction 2 no(g) + cl2(g) → 2 nocl(g) is carried out in a closed vessel. if the partial pressure of no is decreasing at a ra

BARSIC [14]

Answer:

92.0 torr/min.

Explanation:

For the reaction: 2NO(g) + Cl₂(g) → 2NOCl(g).

∵ The rate of the reaction = - 1/2(ΔP)NO/Δt = - (ΔP)Cl₂/Δt = 1/2(ΔP)NOCl/Δt.

∵ (ΔP)NO/Δt = - 184 torr/min.

∴ The rate of change of the total pressure in the vessel = - 1/2(ΔP)NO/Δt = (- 1/2)(- 184 torr/min) = 92.0 torr/min.

4 0

4 years ago

When iron(III) oxide reacts with hydrochloric acid, iron(III) chloride and water are formed. How many grams of iron(III) chlorid

Aleksandr [31]

Answer: The mass of iron (III) chloride produced is 14.81 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For iron(III) oxide:

Given mass of iron(III) oxide = 10.0 g

Molar mass of iron(III) oxide = 159.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of iron(III) oxide}=\frac{10.0g}{159.7g/mol}=0.0626mol$

For hydrochloric acid:

Given mass of hydrochloric acid = 10.0 g

Molar mass of hydrochloric acid = 36.5 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrochloric acid}=\frac{10.0g}{36.5g/mol}=0.274mol$

The chemical equation for the reaction of iron (III) oxide and hydrochloric acid follows:

$Fe_2O_3+6HCl\rightarrow 2FeCl_3+3H_2O$

By Stoichiometry of the reaction:

6 moles of hydrochloric acid reacts with 1 mole of iron (III) oxide

So, 0.274 moles of hydrochloric acid will react with = $\frac{1}{6}\times 0.274=0.0456mol$ of iron (III) oxide

As, given amount of iron (III) oxide is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

6 moles of hydrochloric acid produces 2 moles of iron (III) chloride

So, 0.274 moles of hydrochloric acid will produce = $\frac{2}{6}\times 0.274=0.0913moles$ of iron (III) chloride

Now, calculating the mass of iron (III) chloride from equation 1, we get:

Molar mass of iron (III) chloride = 162.2 g/mol

Moles of iron (III) chloride = 0.0913 moles

Putting values in equation 1, we get:

$0.0913mol=\frac{\text{Mass of iron (III) chloride}}{162.2g/mol}\\\\\text{Mass of iron (III) chloride}=(0.0913mol\times 162.2g/mol)=14.81g$

Hence, the mass of iron (III) chloride produced is 14.81 grams

7 0

3 years ago