The volume of CO₂ at STP = 2.8 L
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Further explanation
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Given
21 gram of sodium hydrogen carbonate-NaHCO₃
Required
Volume of CO₂
Solution
The decomposition of sodium bicarbonate into sodium carbonate, carbon dioxide, and water :
2 NaHCO₃(s) → Na₂CO₃(s) + CO₂(g) + H₂O(g)
mol of NaHCO₃ :
= mass : MW NaHCO₃
= 21 g : 84 g/mol
= 0.25
From the equation, mol ratio of NaHCO₃(s) :CO₂(g) = 2 : 1, so mol CO₂ :
= 1/2 x mol NaHCO₃
= 1/2 x 0.25
= 0.125
At STP, 1 mol gas = 22.4 L, so for 0.125 mol :
= 0.125 x 22.4 L
= 2.8 L
Answer:
Likely to gain electrons
Explanation:
The atom shown is likely to gain additional electrons to complete its electronic configuration.
- Since this is a neutral specie, the number of protons and electrons are the same.
- The atom has 16 electrons
- the number of valence electrons is 6
- If the atom gains two additional electrons, the octet configuration is attained
- Also, the atom can lose 6 electrons to become an octet
The atom will prefer to gain additional 2 electrons to give an octet configuration.
The particle that adds mass but no charge to the atomic nucleus is the neutron.
The nucleus contains both protons and neutrons.
Protons and neutrons have about the same mass.
However, protons have a positive charge, while <em>neutrons have no charge</em>,
Explanation:
Hello, let's observe the given data first. The data says The conc of magnesium chloride solution is 0.117 mol/L that means in one litre solution 0.117 mole MgCl2 are present. but we have to find the moles of magnesium chloride, magnesium ions & chloride ions in 16.4 mL solution.
Now 16.4 ml solution contains 1.91× 10-³ magnesium chloride.
Before finding the amount of ions in solution let's have a look at dissociation of magnesium chloride.
<em>One mole of Magnesium chloride produces 1 mole of magnesium & 2 mole of chloride ions.</em>
Hence 1.91× 10-³ moles of magnesium chloride will produce 1.91 × 10-³ moles of magnesium ion & 3.82 × 10-³ moles of chloride ions.
