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Nata [24]
3 years ago
15

Use the unit circle to find sec (-90)

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0

Using the unit circle, you can visualise the secant as follows:

  1. Draw the vertical line passing trough (1,0)
  2. Extend the radius until it meets this line at point P
  3. The length of OP is the secant of your angle.

Since -90 means that the radius points downwards, it means that the radius is vertical as well, and thus it never meets the vertical line through (1,0).

Thus, the secant is not defined at -90.

In fact, if we switch back to the function notation, we can confirm this claim, since we have

\sec(x)=\dfrac{1}{\cos(x)}\implies \sec(-90)=\dfrac{1}{\cos(-90)}=\dfrac{1}{0}

which is undefined.

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Uber charges 1.75 for pickup plus 0.50 per mile. Omar paid 4.25 for a ride. How many miles did he travel?
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Omar Traveled 5 miles

Step-by-step explanation:

First set up a two step equation, .50x (x is our variable for miles driven) then +1.75= 4.25. Then Subtract 1.75 from itself and from 4.25. You get 2.5, bring everything down. You are now left with .50x=2.5 divide each side by .50 . 2.5 divided by .50 equals 5 and .50 divided by itself is zero, bring down the x and the 2.5. It should now look like this x = 2.5 That is your answer.

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A line segment has endpoints at (2,10) and (10,2). What are the coordinates of the midpoint of the line segment?
IrinaVladis [17]

Answer:

(6,6)

Step-by-step explanation:

The midpoint formula is (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} ). Substitute (2,10) and (10,2) into this formula and simplify.

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} ) \\(\frac{2+10}{2},\frac{10+2}{2} ) \\(\frac{12}{2},\frac{12}{2} ) \\(6,6)

8 0
4 years ago
The arch beneath a bridge is​ semi-elliptical, a​ one-way roadway passes under the arch. The width of the roadway is 38 feet and
forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

\frac{x^2}{a^2}+\frac{y^2}{b^2}

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

a=\frac{38}{2}=19ft

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}

and we can simplify the equation, so we get:

\frac{x^2}{361}+\frac{y^2}{144}

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

\frac{y^{2}}{144}=1-\frac{x^{2}}{361}

y^{2}=144(1-\frac{x^{2}}{361})

we can add everything inside parenthesis so we get:

y^{2}=144(\frac{361-x^{2}}{361})

and take the square root on both sides, so we get:

y=\sqrt{144(\frac{361-x^{2}}{361})}

and we can simplify this so we get:

y=\frac{12}{19}\sqrt{361-x^{2}}

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

y=\frac{12}{19}\sqrt{361-(8)^{2}}

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.

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3 years ago
A team digs 12 holes every 20 hours. How many holes<br> do they dig per hour?
olya-2409 [2.1K]

Answer:

Step-by-step explanation:

12 / 20 = 0.6 holes per hour

7 0
3 years ago
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