Answer:
<h2>y = 5x + 11</h2>
Step-by-step explanation:


Answer:
.
Step-by-step explanation:
Answer:
maybe the answer is 12 units.
32.5 % of lab are wireless devices
<em><u>Solution:</u></em>
Given that there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices
Now we can first find out total number of computers and devices in lab
total number of computers and devices in lab = 30 computers - 3 + 13 wireless devices
total number of computers and devices in lab = 30 - 3 + 13 = 40
So there are 40 computers and wireless devices in lab
<em><u>To find: what percent of the lab are wireless devices</u></em>
So we have to find what percent of 40 is 13
Let "a" be the required percent
a % of 40 = 13

32.5 % of of lab are wireless devices
Answer:
Correct option is (C).
The possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.
Step-by-step explanation:
The <em>p</em>-value is the probability of acquiring a result as extreme as the observed result, assuming the null hypothesis statement is true.
The <em>p</em> value of a test is:
Left-tailed test:
Right-tailed test:
.
Here,
TS = Test statistic
ts = computed value of the test statistic.
The two-tailed <em>p</em>-value is:
or
.
The <em>p</em>-value of the two tailed test is, 0.44.
Compute the <em>p</em>-value for one-tailed test a follows:


Thus, the possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.
The correct option is (C).