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Jlenok [28]
3 years ago
13

A bag contains 2 red, 4 blue, and 4 yellow marbles. What is the probability of pulling a red marble, putting the marble back, an

d then pulling a blue marble.
10%

8%

13.82%

14%
Mathematics
1 answer:
sdas [7]3 years ago
8 0

Answer:

B.) 8%

Step-by-step explanation:

Answer: B.) 8%

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Last math question.
siniylev [52]

Answer:

<h2>y = 5x + 11</h2>

Step-by-step explanation:

\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-\text{slope}\\b-\text{y-intercept}\\\\\text{Let}\\\\k:y=m_1x+b_1\\l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\k\ ||\ l\iff m_1=m_2\\=========================

\text{We have}\ y=5x+2\to m_1=5\\\\\text{therefore}\ m_2=5.\\\\\text{Put the value of the slope and the coordinates of the given point (-2, 1)}\\\text{to the equation of a line:}\\\\1=5(-2)+b\\1=-10+b\qquad\text{add 10 to both sides}\\1+10=-10+10+b\\11=b\to b=11\\\\\text{Finally:}\\\\y=5x+11

5 0
3 years ago
10. Shown is a circle centre o
Aleksandr [31]

Answer:

.

Step-by-step explanation:

6 0
3 years ago
Someone help me please
Ksivusya [100]

Answer:

maybe the answer is 12 units.

8 0
2 years ago
If there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices, about w
Liula [17]

32.5 % of lab are wireless devices

<em><u>Solution:</u></em>

Given that there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices

Now we can first find out total number of computers and devices in lab

total number of computers and devices in lab = 30 computers - 3 + 13 wireless devices

total number of computers and devices in lab = 30 - 3 + 13 = 40

So there are 40 computers and wireless devices in lab

<em><u>To find: what percent of the lab are wireless devices</u></em>

So we have to find what percent of 40 is 13

Let "a" be the required percent

a % of 40 = 13

\frac{a}{100} \times 40 = 13\\\\a = \frac{13 \times 100}{40}\\\\a = 32.5

32.5 % of of lab are wireless devices

6 0
3 years ago
An experimenter conducted a two-tailed hypothesis test on a set of data and obtained a p-value of 0.44. If the experimenter had
Lyrx [107]

Answer:

Correct option is (C).

The possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.

Step-by-step explanation:

The <em>p</em>-value is the probability of acquiring a result as extreme as the observed result, assuming the null hypothesis statement is true.

The <em>p</em> value of a test is:

Left-tailed test: P(TS

Right-tailed test: P(TS>ts) = 1- P(TS.

Here,

TS = Test statistic

ts = computed value of the test statistic.

The two-tailed <em>p</em>-value is: 2P(TS or 2P(TS>ts).

The <em>p</em>-value of the two tailed test is, 0.44.

Compute the <em>p</em>-value for one-tailed test a follows:

  • For a left-tailed test:

            2P(TS

  • For a right-tailed test:

            P(TS>ts) = 1- P(TS

Thus, the possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.

The correct option is (C).

3 0
3 years ago
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