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3 years ago

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Calculate the pressure in atmospheres exerted by 10.0 moles of hydrogen gas at 293 Kelvin if it is stored in a 7.50 liter contai

ner. Your value should be a decimal number written to three significant figures. Given: R = 0.08205 liter · atmosphere/mole · Kelvin

1 answer:

mel-nik [20]3 years ago

5 0

You rearrange the ideal gas law equation to solve for the pressure by just plugging in the given values.

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Which of these equations are correct? Select all that apply

nikitadnepr [17]

Answer:

The answer to your question is below

Explanation:

There are 4 laws of gases

- Charles

$\frac{V1}{T1} = \frac{V2}{T2}$

- Gay Lussac

$\frac{P1}{T1} = \frac{P2}{T2}$

- Boyle - Mariotte

P1V1 = P2V2

- General law of gases

$\frac{P1V1}{T1} = \frac{P2V2}{T2}$

Let's use these formulas to answer the question

p2 = V2/P1 This is not a law of gases

p1= V1/k This formula is similar to Boyle mariotte equation

but is not.

V2 = k/P2 This equation is correct is Boyle Mariotte formula

V2 = P1V1/ P2 This equation is also correct is Boyle Mariotte formula

V1 = P1/P2 (V2) This equation is incorrect

P2 = (P1) V1/V2 This equation is correct is Boyle mariotte formula

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4 years ago

How do whales, bats, and dolphins use echolocation?

Nataly [62]

I feel like all of them are true

8 0

3 years ago

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Sugar when dissolved into water, propose whether the compound forms atoms, molecules or lattices. Justify you answer

kirza4 [7]

Answer:

atoms

Explanation:

for sugar to dissolve in water hydaration must be equal to or greater than the lattice energy or molecular forces so when the molecular forces breaks new atoms are formed for recombination in new compound

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3 years ago

When two hydrogen nuclei combine to form one helium nucleus, nuclear fusion has taken place.. . True or False

Aleks [24]

True.

Nuclear Fusion is a reaction process that involves combination of smaller nuclei to form larger one.

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3 years ago

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Determine the quality of a two-phase liquid-vapor mixture of (a) H.O at 100°C with a specific volume of 0.8 m /kg. (b) Refrigera

Paul [167]

Answer:

a) 0.478 4

b) 1.45 × 10⁻⁶

Explanation:

A two phase liquid-vapor mixture

a) Given:

Temperature of H.O = 100°C

Specific volume of mixture, v = 0.8

now, we know

The specific volume of water at 100°C, vf = 0.001043 m³/kg

and,specific volume of steam At 100°C , vg = 1.671 m³/kg

also,

Specific volume, v = [ vf + x × (vg - vf ) ]

here, x is the quality

therefore, we get

0.8 = 0.001043 + [ x × (1.671 - 0.001043) ]

or

0.798957 = x × 1.669957

or

x = 0.478 4

b) Temperature of refrigerant = 0°C

Specific volume of refrigerant, v = 0.7721 cm³/g = 0.7721 × 10⁻³ m³/kg

Specific volume of fluid, vf = 7.72 × 10⁻⁴ m³/kg

Specific volume of gas, vg = 0.06930 m³/kg

Now,

Specific volume of two-phase mixture, v = [ vf + x × (vg - vf ) ]

on substituting the values in the above equation, we get

0.7721 × 10⁻³ = 7.72 × 10⁻⁴ + [ x × (0.06930 - 7.72 × 10⁻⁴ ) ]

or

x = 1.45 × 10⁻⁶

4 0

3 years ago