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LuckyWell [14K]

2 years ago

5

According to the VSEPR theory, what is the shape of a molecule that has a central atom bound to three other atoms with no lone p

airs of electrons

1 answer:

Masja [62]2 years ago

4 0

It's should be trigonal planar if I remember correctly

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Explain how mixture melting points can be used to distinguish between two compounds

Over [174]

generally melting point of mixture is always different from melting point of pure compound

lets say you have a two compounds called A and B

and you have a unknown compound called X which can be either A or B

now your target is to find unknown is really A or B right?

take some amount of X and mix it with A and B separately

out of these two mixtures one will be pure compound (because we initially assume that unknown can be either A or B)

suppose X + A is same melting with A then X is A

X +B will be less than the melting point of A or

suppose X+B is same melting point like B then X is B

X+A will be less than melting point of B

5 0

3 years ago

1) How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7g Fe? Show your work.

klasskru [66]

1.) is157.7 g
<span>moles Fe = 209.7 g/ 55.847 g/mol=3.75
the ratio between Fe and CO is 2 : 3
moles CO = 3.75 x 3 /2 =5.63
mass CO = 5.63 mol x 28.01 g/mol=157.7 g

2.) is </span><span>1.06 moles
</span>48.7/23 = 2.12 moles sodium
<span>2.12/2 x 24 = 25.44dm^3 hydrogen = 1.06 moles </span>
1.06 X 6.02x10^23 = 1.204x10^24 molecules of hydrogen.

3.) is 91.8
<span>8.3 moles H2S x (2 moles H2O / 2 moles H2S) = 8.3 moles H2O = theoretical amount produced. </span><span>8.3 moles H2O x (18.0 g H2O / 1 mole H2O) = 149 g H2O produced theoretically. </span><span>% yield = (actual amount produced / theoretical amount) x 100 = (137.1 g / 149 g) x 100 = 91.8 </span>

6 0

2 years ago

Read 2 more answers

A 1 l container contains O2 gas at stp. if the diameter of the O2 molecule is 3.75 * 10^-10 m the mean free path of the o2 molec

Luba_88 [7]

The mean free path of the O₂ molecule is $5.97*10^{-5}$ m.

The mean free path of the O₂ molecule is calculated by the formula -

λ = $\frac{1}{\sqrt{2}*\pi *d^{2}*n}$

In this formula, λ represents mean free path of gas, d represents diameter and n is number of molecules.

As per the known fact, 1 mole of gas occupies 22.4 liter at STP.

So. 1 liter of O₂ gas will have number of moles = $\frac{1*1}{22.4}$

Number of moles = 0.045

Also, we are aware that 1 mole contains $6.02*10^{23}$ molecules.

So, 0.045 moles will contain number of molecules = $6.02*10^{23}*0.045$

Number of molecules = $2.7*10^{22}$ molecules

Now, keeping the values in formula to find mean free path of gas -

λ = $\frac{1}{1.4*3.14*(3.75*10^{-10})^{2} *2.7*10^{22} }$

λ = $\frac{1}{16746.7}$

λ = $5.97*10^{-5}$ m

Hence, the mean free path of the O₂ molecule is $5.97*10^{-5}$ m.

Learn more about calculation of mean free path -

brainly.com/question/25820669

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8 0

2 years ago

What is the answer to this?

beks73 [17]

Answer:

hm step by step try to figure it 9ut

8 0

2 years ago

How will you investigate the relationship between the molecule's temperature and kinetic energy?

devlian [24]

Answer:

The behaviour of gases is described in terms of kinetic theory , which considers the motion of molecules in the gas . The gas link pressure , volume and temperature .

Explanation:

4 0

2 years ago