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SSSSS [86.1K]
3 years ago
10

Find the volume of 20g of H₂ at STP​

Chemistry
1 answer:
ANEK [815]3 years ago
6 0

Answer:224

Explanation:

We should answer it with Stoichiometry

We say: 20 g H2× (1 mol/ 2g)× ( 22.4 lit/ 1 mol) = 224

Means: we have 20 grams and every 2g H2, equals to 1 mol of it and every 1 mol of H2, equals to 22.4 lit( because of STP)

hope you got this:)

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What is the half-life of a compound if 42% of a given sample of the compound decomposes in 60 minutes
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<h3>What is the expression for rate law for first order kinetics?</h3>

The rate law for first order kinetics is

k = \frac{2.303}{t}log\frac{a}{a-x}

Where

k - rate constant

t - time passed by the sample

a - initial amount of the reactant

a-x - amount left after the decay process

<h3>What is expression for half-life of the compound?</h3>

The expression for the half-life of the compound is

t_{\frac{1}{2} }=\frac{0.693}{k}

Where k is the rate constant

<h3>Calculation for the given compound:</h3>

It is given that

t = 60 minutes

a = 100 g

a-x = 100 g - 42 g = 58 g

(Since it is given that 42% of the given compound decomposes)

Then,

k = \frac{2.303}{60}log\frac{100}{58}

  = 9.08 × 10^{-3} years^{-1}

Then, the half-life of the compound is

t_{\frac{1}{2} }=\frac{0.693}{k}

    = \frac{0.693}{9.08*10^{-3} }

    = 76.3 years ≅ 76 years

Therefore, the half-life of the given compound is 76 years.

Learn more about rate law for first order kinetics here:

brainly.com/question/24080964

#SPJ4

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