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3 years ago

Can someone help me wit da question listed in da picture?

Mathematics

2 answers:

insens350 [35]3 years ago

7 0

Answer:

Add 8 to both sides

Step-by-step explanation:

Normally after adding 8 to both sides you'd solve for x by then dividing by -5, but they just want u to explain what to do lol.

Vikentia [17]3 years ago

5 0

Answer:

I think it's add an both sides

Step-by-step explanation:

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5. 4i(-2 - 4i)

Wewaii [24]

Answer:

$4i( - 2 - 4i) = - 8i + 16 \\ \\ 5i.i.( - 2i) = 10i \\ \\ (- 5 - i)(1 + i) = -5-5i-i+1\\=-4-6i$

4 0

2 years ago

Help me pls!!!!!!!!!

Dominik [7]

Answer:

$x^2+18=-9x : x = -3, x = -6$

Step-by-step explanation:

$x^2+18=-9x$

Add 9x to both sides:

$x^2+18+9x=-9x+9x$

Simplify:

$x^2+9x+18=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=1,\:b=9,\:c=18:\quad x_{1,\:2}=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}$

$x =\frac{-9 + \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -3$

$x =\frac{-9 - \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -6$

The solution to the quadratic equation are:

$x=-3,\:x=-6$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day!

6 0

2 years ago

Solve the equation for all values of x.<br> (8x+9)(49x^2-100)=0

Liono4ka [1.6K]

Answer:

$x = \frac{-9}{8} , \frac{-10}{7} , \frac{10}{7}$

Step-by-step explanation:

8x+9=0

8x=-9

$x = \frac{-9}{8}$

$49x^{2}-100 = 0$

$(7x)^{2} -10^{2} =0$ ,

$(7x+10)(7x-10)=0$

$7x+10=0, 7x-10=0$

$7x=-10, 7x=10$

$x=-\frac{-10}{7}$ , $x = \frac{10}{7}$

4 0

2 years ago

Simplify the expression (2-5 root 6) times 3 root 2

lys-0071 [83]

Answer:

6(√2 - 5√3).

Step-by-step explanation:

3√2 ( 2 - 5 √6)

= 6√2 - 15√12

= 6√2 - 15√4√3

= 6√2 - 30√3

= 6(√2 - 5√3)

6 0

2 years ago

7x2x2x2 is the prime factorization for which of the following

GaryK [48]

Answer: B) 56

Just multiply all numbers and see which number from the choices match your answers after doing the multiplication! Hope I helped!

3 0

2 years ago