What happens if you remove electrons from a neutral object?

DNA has 2 strands. if the sequence of nucleotides of one strand was known, is it possible to use the information to determine th

ANTONII [103]

DNA has four main components.
Adenine=A
Cytosine=C
Guanine=G
Thymine=T

Since each letter has an opposite it would be possible by considering the pairs.
A:T
C:G

So, if one strand went as so:
AGCCTAGGTAC
The corresponding strand would be mirrored with the match: TCGGATCCTG

3 0

3 years ago

The compound sodium carbonate is a strong electrolyte. Write the reaction when solid sodium carbonate is put into water:

Ludmilka [50]

The compound sodium carbonate is a strong electrolyte because it completely dissociates when placed in water into its component ions. The equation of the reaction can be expressed as:

$Na_2CO_3_{(s)} ---> 2 Na^+_{(aq)} + CO_3^{(2+)}_{(aq)}$

The dissociation leads to the formation of sodium and carbonate ions with the latter held together by its internal covalent bond.

This is unlike weak electrolytes that do not dissociate completely in water or aqueous solutions. Only a small fraction of the solute exists as ions in the solution.

More on strong and weak electrolytes can be found here: brainly.com/question/3410548

7 0

3 years ago

One mole of aluminum atoms has a mass of 27 grams. How many grams are in 9.0 moles of aluminum?

gizmo_the_mogwai [7]

27*9=243 if one mole is equal to 27 grams times that by 9

6 0

3 years ago

A gold nugget has a density of 38.6g/cm3 and a mass of 270.2. what is its volume?

aivan3 [116]

Density is given by the equation D=m/V, were D is density, m is mass in grams, and V is volume in cubic centimeters.

In this problem, we have density and we have mass so we can plug into the equation and solve for V.

38.6=270.2/V

<em>*Multiply both sides by V*</em>

38.6V=270.2

<em>*Divide both sides by 38.6*</em>

V=7

The volume of the gold nugget is 7cm3.

Hope this helps!!

5 0

3 years ago

Read 2 more answers

A waste treatment pond is 50 m long and 25 m wide, and has an average depth of 2 m. The density of the waste is 75.3lbm/ft^3 .Ca

umka21 [38]

Answer:

$W = 6.65 \cdot 10^{6} lbf$

Explanation:

To find the weight (W) of the pond contents first we need to use the following equation:

$W = m\cdot g$ (1)

Where m the mass and g is the gravity

Also, we have that the mass is:

$m = \rho*V$ (2)

Where ρ is the density and V the volume

We cand calculate the volume as follows:

$V = L*w*d$ (3)

Where L is the length, w is the wide and d is the depth

By entering equation (2) and (3) into (1) we have:

$W = \rho*L*w*d*g$

$W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2}$

$W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf$

Therefore, the weight of the pond is 6.65x10⁶ lbf.

I hope it helps you!

6 0

4 years ago