The mole ratio of acetic acid to water in 100 g of vinegar is 0.015 : 0.985.
<h3>What is the mole ratio of acetic acid to water in 100 g of vinegar?</h3>
The mole ratio of acetic acid to water in 100 g of vinegar is determined from their percentage composition.
The percentage composition of acetic acid and water in vinegar is 5% acetic acid and 95% water.
In 100 g of vinegar, there are 5 g of acetic acid and 5 g of water.
Moles = mass/molar mass
molar mass of acetic acid = 62 g/mol
molar mass of water = 18 g/mol
moles of vinegar = 5/62 = 0.08
moles of water = 95/18 = 5.28
total moles = 5.36
Mole ratio of vinegar to water = 0.08/5.36 : 5.28/5.36
Mole ratio of vinegar to water = 0.015 : 0.985
In conclusion, the mole ratio is determined from the percentage composition of acetic acid and water in vinegar.
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Acetic acid activates the bromine and makes it a better electrophile.
<h3>What is bromination?</h3>
When a substance undergoes bromination, bromine is added to the compound as a result of the chemical reaction. After bromination, the result will have different properties from the initial reactant.
<h3>Why is 15M acetic acid used as a solvent for bromination?</h3>
DCM (dichloromethane) requires more time. Acetic acid has protons that can give one of the Br (bromine) a positive charge and activate it. There is a brief loss of aromaticity that calls for high energy activation.
Refer to the attached image for bromination reaction.
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It would be 4.2, hope this helps.
Argon has 24 known isotopes.
